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An organic compound P contains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)
[Atomic mass : Br = 80]
[Atomic mass : Br = 80]
Correct answer is '1'. Can you explain this answer?
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Verified Answer
An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and res...
Molecular formula from calculation comes to be C3H6O i.e., it stands for the following compounds.
VD × 2 = MM
= 29 × 2 = 58
∴ 58 g of ether combines with 2 × 80g Br2
∴ 2.9 g of ether will combines with
Y = 9 and X = 8
Y – X = 9 – 8 = 1
VD × 2 = MM
= 29 × 2 = 58
∴ 58 g of ether combines with 2 × 80g Br2
∴ 2.9 g of ether will combines with
Y = 9 and X = 8
Y – X = 9 – 8 = 1
Most Upvoted Answer
An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and res...
To find the value of Y, we need to determine the molar mass of the organic compound.
Let's assume the compound has a mass of 100g.
Given that the compound contains 62.07% carbon and 10.34% hydrogen, we can calculate the masses of carbon and hydrogen in the compound.
Mass of carbon = 62.07% of 100g = 62.07g
Mass of hydrogen = 10.34% of 100g = 10.34g
We can now calculate the mass of oxygen in the compound by subtracting the masses of carbon and hydrogen from the total mass.
Mass of oxygen = 100g - (62.07g + 10.34g) = 27.59g
To find the moles of each element, we divide the masses by their respective molar masses.
Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Moles of carbon = 62.07g / 12.01 g/mol = 5.17 mol
Moles of hydrogen = 10.34g / 1.01 g/mol = 10.23 mol
Moles of oxygen = 27.59g / 16.00 g/mol = 1.72 mol
The empirical formula of the compound can be determined by dividing the moles of each element by the smallest number of moles.
Empirical formula: C5H10O
The vapour density of the compound is given as 29. The vapour density is the ratio of the molar mass of the compound to the molar mass of hydrogen gas (2 g/mol).
Vapour density = (Molar mass of compound) / (Molar mass of hydrogen gas)
29 = (Molar mass of compound) / 2 g/mol
Molar mass of compound = 29 x 2 g/mol = 58 g/mol
Now, we know that 2.9g of the compound combines with X grams of bromine to give the dibromo addition product.
To find the value of X, we need to determine the molar mass of the dibromo addition product.
The molar mass of bromine (Br) is 79.90 g/mol.
Molar mass of dibromo addition product = (Molar mass of compound) + (2 x Molar mass of bromine)
Molar mass of dibromo addition product = 58 g/mol + (2 x 79.90 g/mol)
Molar mass of dibromo addition product = 217.8 g/mol
Now, we can calculate the value of X using the molar mass of the dibromo addition product.
2.9g / 217.8 g/mol = X g / 1 mol
X = (2.9g / 217.8 g/mol) x 1 mol
X = 0.0133 mol
Therefore, the value of Y is 0.0133 mol.
Let's assume the compound has a mass of 100g.
Given that the compound contains 62.07% carbon and 10.34% hydrogen, we can calculate the masses of carbon and hydrogen in the compound.
Mass of carbon = 62.07% of 100g = 62.07g
Mass of hydrogen = 10.34% of 100g = 10.34g
We can now calculate the mass of oxygen in the compound by subtracting the masses of carbon and hydrogen from the total mass.
Mass of oxygen = 100g - (62.07g + 10.34g) = 27.59g
To find the moles of each element, we divide the masses by their respective molar masses.
Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Moles of carbon = 62.07g / 12.01 g/mol = 5.17 mol
Moles of hydrogen = 10.34g / 1.01 g/mol = 10.23 mol
Moles of oxygen = 27.59g / 16.00 g/mol = 1.72 mol
The empirical formula of the compound can be determined by dividing the moles of each element by the smallest number of moles.
Empirical formula: C5H10O
The vapour density of the compound is given as 29. The vapour density is the ratio of the molar mass of the compound to the molar mass of hydrogen gas (2 g/mol).
Vapour density = (Molar mass of compound) / (Molar mass of hydrogen gas)
29 = (Molar mass of compound) / 2 g/mol
Molar mass of compound = 29 x 2 g/mol = 58 g/mol
Now, we know that 2.9g of the compound combines with X grams of bromine to give the dibromo addition product.
To find the value of X, we need to determine the molar mass of the dibromo addition product.
The molar mass of bromine (Br) is 79.90 g/mol.
Molar mass of dibromo addition product = (Molar mass of compound) + (2 x Molar mass of bromine)
Molar mass of dibromo addition product = 58 g/mol + (2 x 79.90 g/mol)
Molar mass of dibromo addition product = 217.8 g/mol
Now, we can calculate the value of X using the molar mass of the dibromo addition product.
2.9g / 217.8 g/mol = X g / 1 mol
X = (2.9g / 217.8 g/mol) x 1 mol
X = 0.0133 mol
Therefore, the value of Y is 0.0133 mol.
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An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer?
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An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer?.
An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer?.
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An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer?, a detailed solution for An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? has been provided alongside types of An organic compoundPcontains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P)[Atomic mass : Br = 80]Correct answer is '1'. Can you explain this answer? theory, EduRev gives you an
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