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0.2 g of an organic compound was subjected to estimation of nitrogen by Duma's method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _____. [Nearest integer]
(Given: Molar mass of N2 is 28 g mol-1, Molar volume of N2 at STP is 22.4 L)
    Correct answer is '14'. Can you explain this answer?
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    0.2 g of an organic compound was subjected to estimation of nitrogen b...
    Mass of the organic compound = 0.2 g
    Volume of N2 gas evolved at STP = 22.4 mL
    Mass of N2 gas evolved  
    Percentage of nitrogen in the compound 
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    0.2 g of an organic compound was subjected to estimation of nitrogen b...
    To calculate the percentage of nitrogen in the organic compound, we need to determine the amount of nitrogen present in the 0.2 g sample.

    First, we need to calculate the number of moles of nitrogen gas evolved during the Dumas method.

    1. Calculate the number of moles of nitrogen gas:
    - Molar volume of nitrogen gas at STP = 22.4 L
    - Volume of nitrogen gas evolved = 22.400 mL = 22.400 * 10^(-3) L
    - Moles of nitrogen gas = (Volume of nitrogen gas evolved)/(Molar volume of nitrogen gas)
    = (22.400 * 10^(-3) L) / (22.4 L)
    = 1 * 10^(-3) mol

    Next, we need to calculate the number of moles of nitrogen in the compound.

    2. Calculate the number of moles of nitrogen in the compound:
    - Molar mass of nitrogen gas (N2) = 28 g/mol
    - Moles of nitrogen in the compound = Moles of nitrogen gas * (Molar mass of nitrogen gas)/(Molar mass of N2)
    = (1 * 10^(-3) mol) * (28 g/mol) / (28 g/mol)
    = 1 * 10^(-3) mol

    Finally, we can calculate the percentage of nitrogen in the compound.

    3. Calculate the percentage of nitrogen in the compound:
    - Mass of nitrogen in the compound = Moles of nitrogen in the compound * Molar mass of N2
    = (1 * 10^(-3) mol) * (28 g/mol)
    = 0.028 g

    - Percentage of nitrogen in the compound = (Mass of nitrogen in the compound)/(Mass of the sample) * 100
    = (0.028 g)/(0.2 g) * 100
    = 14%

    Therefore, the percentage of nitrogen in the compound is 14%.
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    0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _____. [Nearest integer](Given: Molar mass of N2 is 28 g mol-1, Molar volume of N2 at STP is 22.4 L)Correct answer is '14'. Can you explain this answer?
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    0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _____. [Nearest integer](Given: Molar mass of N2 is 28 g mol-1, Molar volume of N2 at STP is 22.4 L)Correct answer is '14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _____. [Nearest integer](Given: Molar mass of N2 is 28 g mol-1, Molar volume of N2 at STP is 22.4 L)Correct answer is '14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _____. [Nearest integer](Given: Molar mass of N2 is 28 g mol-1, Molar volume of N2 at STP is 22.4 L)Correct answer is '14'. Can you explain this answer?.
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