JEE Exam  >  JEE Questions  >  In Carius method of estimation of halogens, 2... Start Learning for Free
In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :
(at. mass Ag =108; Br = 80)
  • a)
    48
  • b)
    60
  • c)
    24
  • d)
    36
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In Carius method of estimation of halogens, 250 mg of an organic compo...
First we have to find moles of br in rex. as 141/188
now mass of br in compound is 141*80/188
so %br=141*80*100/188*250=24
Free Test
Community Answer
In Carius method of estimation of halogens, 250 mg of an organic compo...
Mass of substance = 250 mg = 0.250 g
Mass of AgBr = 141 mg = 0.141 g
1 mole of AgBr = 1 g atom of Br
188 g of AgBr = 80 g of Br
∴ 188 g of AgBr contain bromine = 80 g
0.141 g of AgBr contain bromine 
This much amount of bromine present in 0.250 g of organic compound
Explore Courses for JEE exam

Similar JEE Doubts

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer?
Question Description
In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer?.
Solutions for In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is :(at. mass Ag =108; Br = 80)a)48b)60c)24d)36Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev