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A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-
  • a)
    2.3 × 10–2
  • b)
    3.3 × 10–2
  • c)
    3.3 × 10–4
  • d)
    4.3 × 10–2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A paramagnetic substance in the form of a cube with sides 1 cm has a m...




= 0.33 × 10–3 = 3.3 × 10–4
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A paramagnetic substance in the form of a cube with sides 1 cm has a m...
To solve this problem, we need to use the formula for the magnetic dipole moment:

Magnetic dipole moment (m) = magnetic moment per unit volume (μ) × volume (V)

Given:
Magnetic dipole moment (m) = 20 A/m
Volume (V) = side^3 = 1 cm^3 = (1 × 10^-2 m)^3 = 1 × 10^-6 m^3

Substituting these values into the formula, we get:

20 A/m = μ × 1 × 10^-6 m^3

Rearranging the equation to solve for μ, we get:

μ = (20 A/m) / (1 × 10^-6 m^3)

Simplifying, we get:

μ = 20 × 10^6 A/m^4

Therefore, the magnetic moment per unit volume of the cube is 20 × 10^6 A/m^4.
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A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-a)2.3 × 10–2b)3.3 × 10–2c)3.3 × 10–4d)4.3 × 10–2Correct answer is option 'C'. Can you explain this answer?
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A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-a)2.3 × 10–2b)3.3 × 10–2c)3.3 × 10–4d)4.3 × 10–2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-a)2.3 × 10–2b)3.3 × 10–2c)3.3 × 10–4d)4.3 × 10–2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-a)2.3 × 10–2b)3.3 × 10–2c)3.3 × 10–4d)4.3 × 10–2Correct answer is option 'C'. Can you explain this answer?.
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