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If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2)= 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :-a)5√5b)(10)2/3c)5(21/3)d)5Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2)= 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :-a)5√5b)(10)2/3c)5(21/3)d)5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2)= 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :-a)5√5b)(10)2/3c)5(21/3)d)5Correct answer is option 'D'. Can you explain this answer?.

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