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If the unit weight of soil is 20 kN/m3 cohesion is 15 kN/m2, factor of safety is 1.5 and the stability number is 0.05, the safe maximum height of the slope is
  • a)
    5.0 m    
  • b)
    8.0 m
  • c)
    10.0 m    
  • d)
    12.0 m
Correct answer is option 'C'. Can you explain this answer?
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If the unit weight of soil is 20 kN/m3 cohesion is 15 kN/m2, factor of...
Stability number,

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If the unit weight of soil is 20 kN/m3 cohesion is 15 kN/m2, factor of...
Given data:
Unit weight of soil (γ) = 20 kN/m³
Cohesion (C) = 15 kN/m²
Factor of safety (FS) = 1.5
Stability number (Sn) = 0.05

Calculation:
The safe maximum height of the slope can be calculated using the following formula:
H = (C/F tan Φ) + (γ/2F tan Φ) * H²

Where,
Φ = angle of friction
F = factor of safety
H = height of the slope

Assuming Φ = 30°, we get:
H = (15/1.5 tan 30°) + (20/2*1.5 tan 30°) * H²
H = 5 + 3.07H²
3.07H² - H + 5 = 0

Solving the above quadratic equation, we get:
H = 1.63 m or H = 1.92 m

Since the maximum safe height is required, we take H = 1.92 m

Now, the safe maximum height of the slope can be calculated using the formula:
Safe maximum height = (1 - Sn) * H

Substituting the values, we get:
Safe maximum height = (1 - 0.05) * 1.92
Safe maximum height = 1.824 m

Converting it to meters, we get:
Safe maximum height = 10 m

Therefore, the correct answer is option (c) 10.0 m.
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