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 A constraint in equation 5x1 - 3x2 ≤ -5 is converted as, (3x2 + α1) - (5x1 + -s1) = 5
Then 's1' is called as
  • a)
    basic variable
  • b)
    artificial variable
  • c)
    surplus variable
  • d)
    non-basic variable
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A constraint in equation5x1 - 3x2 ≤ -5 is converted as, (3x2 + &alp...

This is used to convert constraint in equation.

Thus s1 is the surplus variable.
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Most Upvoted Answer
A constraint in equation5x1 - 3x2 ≤ -5 is converted as, (3x2 + &alp...


Explanation:

Surplus Variable:

A surplus variable is introduced when converting a less than or equal to constraint into an equation in standard form in linear programming. In this case, the surplus variable (s1) is added to balance the equation and make it an equality. The surplus variable represents the amount by which the left-hand side of the inequality exceeds the right-hand side.

Identification of Surplus Variable:

- The original constraint 5x1 - 3x2 ≤ -5 is converted to (3x2 + α1) - (5x1 + -s1) = 5.
- Here, the variable s1 is introduced to balance the equation and turn the inequality into an equality.
- The surplus variable s1 is associated with the original x1 term in the constraint.

Role of Surplus Variable:

- The surplus variable helps in transforming the inequality constraint into an equation that can be used in linear programming.
- It allows for the comparison of the resources used (the left-hand side of the equation) with the available resources (the right-hand side of the equation).
- The surplus variable helps in determining the feasibility and optimality of the solution in linear programming problems.

Therefore, in the given equation 5x1 - 3x2 ≤ -5, the variable s1 is called a surplus variable as it is introduced to balance the equation and convert the constraint into an equation in standard form.
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