Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  Language L1 is polynomial time reducible to l... Start Learning for Free
Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?
I. If L4 ∈ P , L2 ∈ P
II If L, ∈ P or L3e P, then L2∈ P
III. L, ∈ P, if and only if L3∈ P
IV. If L4 ∈ P, then L1 ∈ P and L3 ∈ P
  • a)
    II only
  • b)
    III only
  • c)
    I and IV only
  • d)
    I only
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Language L1 is polynomial time reducible to language L2. Language L3 i...
if L1 ∈ P we cannot say anything about L2 from 
Since we cannot say anything about L2 therefore we cannot say anything about L3 either from 
So Statement III is false.
IV. If L4∈ P, then L1 ∈ P and L3 ∈ P is true.
If L4 ∈ P then fromwe can get that L2∈ P.
and from  we can now get that  L3 ∈ P 
also from we can get that L1 ∈ P
So Statement IV is true.
View all questions of this test
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Question Description
Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Language L1 is polynomial time reducible to language L2. Language L3 is polynomial time reducible to L2, which in turn is polynomial time reducible to language L4. Which of the following is/are True?I. If L4 ∈ P , L2 ∈ PIIIf L, ∈ P or L3e P, then L2∈ PIII. L, ∈ P, if and only if L3∈ PIV. If L4 ∈ P, then L1 ∈ P and L3 ∈ Pa)II onlyb)III onlyc)I and IV onlyd)I onlyCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev