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In a counter flow heat exchanger, the product of specific heat and mass flow rate is same for the hot and cold fluids. If NTU is equal to 0.5 then the effectiveness of the heat exchanger is
- a)1
- b)0.5
- c)0.33
- d)0.2
Correct answer is option 'C'. Can you explain this answer?
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Explanation:
Given Information:
In a counter flow heat exchanger, the product of specific heat and mass flow rate is the same for the hot and cold fluids. NTU = 0.5
Calculation:
- Effectiveness of a heat exchanger is given by the formula:
\[ \varepsilon = 1 - e^{-NTU(1 - C)} \]
- Given NTU = 0.5 and the product of specific heat and mass flow rate is the same for both fluids, i.e., C_hot = C_cold = C
- Substitute the values in the formula:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} \]
- Since C_hot = C_cold = C, we have:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} \]
- Since C_hot = C_cold = C, we can simplify the equation further:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} \]
- Simplifying the equation further, we get:
\[ \varepsilon = 1 - e^{-0.5} \approx 0.33 \]
Therefore, the effectiveness of the heat exchanger is approximately 0.33, which corresponds to option 'C'.
Given Information:
In a counter flow heat exchanger, the product of specific heat and mass flow rate is the same for the hot and cold fluids. NTU = 0.5
Calculation:
- Effectiveness of a heat exchanger is given by the formula:
\[ \varepsilon = 1 - e^{-NTU(1 - C)} \]
- Given NTU = 0.5 and the product of specific heat and mass flow rate is the same for both fluids, i.e., C_hot = C_cold = C
- Substitute the values in the formula:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} \]
- Since C_hot = C_cold = C, we have:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} \]
- Since C_hot = C_cold = C, we can simplify the equation further:
\[ \varepsilon = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} = 1 - e^{-0.5(1 - C)} \]
- Simplifying the equation further, we get:
\[ \varepsilon = 1 - e^{-0.5} \approx 0.33 \]
Therefore, the effectiveness of the heat exchanger is approximately 0.33, which corresponds to option 'C'.
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In a counter flow heat exchanger, the product of specific heat and mass flow rate is same for the hot and cold fluids.If NTU is equal to 0.5 then the effectiveness of the heat exchanger isa)1b)0.5c)0.33d)0.2Correct answer is option 'C'. Can you explain this answer?
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In a counter flow heat exchanger, the product of specific heat and mass flow rate is same for the hot and cold fluids.If NTU is equal to 0.5 then the effectiveness of the heat exchanger isa)1b)0.5c)0.33d)0.2Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a counter flow heat exchanger, the product of specific heat and mass flow rate is same for the hot and cold fluids.If NTU is equal to 0.5 then the effectiveness of the heat exchanger isa)1b)0.5c)0.33d)0.2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a counter flow heat exchanger, the product of specific heat and mass flow rate is same for the hot and cold fluids.If NTU is equal to 0.5 then the effectiveness of the heat exchanger isa)1b)0.5c)0.33d)0.2Correct answer is option 'C'. Can you explain this answer?.
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