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In certain heat exchanger, both the fluids have identical mass flow rate specific heat product. The hot fluid enters at 76°C and leaves at 47°C, and the cold fluid entering at 28°C leave at 55°C, the effectiveness of the HE is
[1997]
  • a)
    0.16
  • b)
    0.60
  • c)
    0.72
  • d)
    1.0
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In certain heat exchanger, both the fluids have identical mass flow ra...

Here, Ch = Cc.
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In certain heat exchanger, both the fluids have identical mass flow ra...
°F and leaves at 140°F, while the cold fluid enters at 50°F. If the overall heat transfer coefficient is 250 BTU/(hr·ft²·°F), calculate the outlet temperature of the cold fluid.

To solve this problem, we can use the energy balance equation:

Q = m * Cp * (T_out - T_in)

Where:
Q = Heat transfer rate
m = Mass flow rate
Cp = Specific heat
T_out = Outlet temperature
T_in = Inlet temperature

Since both fluids have identical mass flow rate specific heat product, we can assume that m1 * Cp1 = m2 * Cp2.

Let's assume the mass flow rate of the hot fluid is m1 and the mass flow rate of the cold fluid is m2. Also, let's assume the specific heat of both fluids is Cp.

For the hot fluid:
Q_hot = m1 * Cp * (T_hot_out - T_hot_in)

For the cold fluid:
Q_cold = m2 * Cp * (T_cold_out - T_cold_in)

Since the heat transfer rate is the same for both fluids, we can equate the two equations:

m1 * Cp * (T_hot_out - T_hot_in) = m2 * Cp * (T_cold_out - T_cold_in)

Simplifying the equation, we get:

(T_hot_out - T_hot_in) = (T_cold_out - T_cold_in)

Substituting the given values:
(T_hot_out - 76°F) = (140°F - T_cold_in)

Rearranging the equation:
T_hot_out = 140°F - T_cold_in + 76°F
T_hot_out = 216°F - T_cold_in

Substituting this value back into the earlier equation:
(216°F - T_cold_in) - 76°F = (T_cold_out - T_cold_in)

Simplifying further:
140°F - T_cold_in = T_cold_out - T_cold_in

Since the mass flow rate specific heat product is the same for both fluids, we can cancel out the mass flow rate and specific heat terms:

140°F = T_cold_out

Therefore, the outlet temperature of the cold fluid is 140°F.
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In certain heat exchanger, both the fluids have identical mass flow rate specific heat product. The hot fluid enters at 76°C and leaves at 47°C, and the cold fluid entering at 28°C leave at 55°C, the effectiveness of the HE is[1997]a)0.16b)0.60c)0.72d)1.0Correct answer is option 'B'. Can you explain this answer?
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In certain heat exchanger, both the fluids have identical mass flow rate specific heat product. The hot fluid enters at 76°C and leaves at 47°C, and the cold fluid entering at 28°C leave at 55°C, the effectiveness of the HE is[1997]a)0.16b)0.60c)0.72d)1.0Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In certain heat exchanger, both the fluids have identical mass flow rate specific heat product. The hot fluid enters at 76°C and leaves at 47°C, and the cold fluid entering at 28°C leave at 55°C, the effectiveness of the HE is[1997]a)0.16b)0.60c)0.72d)1.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In certain heat exchanger, both the fluids have identical mass flow rate specific heat product. The hot fluid enters at 76°C and leaves at 47°C, and the cold fluid entering at 28°C leave at 55°C, the effectiveness of the HE is[1997]a)0.16b)0.60c)0.72d)1.0Correct answer is option 'B'. Can you explain this answer?.
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