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A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B?
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A manometer connected 2 flasks contains an oil density 0.847g/cc .The ...
The pressure difference between the two flasks can be calculated using the difference in height of the oil column in the manometer arms and the density of the oil. The pressure difference is given by the equation:
ΔP = ρgh
where ΔP is the pressure difference, ρ is the density of the oil (0.847 g/cc), g is the acceleration due to gravity (9.81 m/s^2), and h is the height difference between the two arms of the manometer.
Substituting in the values given, the pressure difference is:
ΔP = (0.847 g/cc)(9.81 m/s^2)(0.74 m) = 5.74 kPa
Since the pressure in flask A is greater than the pressure in flask B, the pressure in flask B can be calculated by subtracting the pressure difference from the pressure in flask A:
P_B = P_A - ΔP = 97.7 kPa - 5.74 kPa = 91.96 kPa
So, the pressure of the gas in flask B is approximately 92 kPa.
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Most Upvoted Answer
A manometer connected 2 flasks contains an oil density 0.847g/cc .The ...
Given information:
- Density of oil: 0.847 g/cc
- Height of oil in flask A: 74 cm higher than the oil in flask B
- Pressure of gas in flask A: 97.7 kPa
To find:
- Pressure of gas in flask B
Assumptions:
- The density of the oil remains constant throughout the experiment.
- The height difference between the oil levels is the only factor affecting the pressure difference.
Explanation:
1. Understanding Manometer:
A manometer is a device used to measure the pressure of a gas. It consists of a U-shaped tube filled with a liquid, in this case, oil. The pressure difference between the two arms of the manometer is determined by the height difference of the liquid in the arms.
2. Pressure Difference in the Manometer:
The pressure difference between the two arms of the manometer is given by the formula:
ΔP = ρgh
Where:
- ΔP is the pressure difference
- ρ is the density of the liquid (oil)
- g is the acceleration due to gravity
- h is the height difference between the liquid levels in the two arms
3. Calculating Pressure of Gas in Flask B:
In this case, the height difference between the oil levels in flask A and flask B is given as 74 cm. Using the formula for pressure difference, we can calculate the pressure of gas in flask B.
ΔP = ρgh
Let's calculate the pressure difference:
ΔP = (0.847 g/cc) * (9.8 m/s^2) * (0.74 m)
ΔP = 6.1117 kPa
4. Pressure of Gas in Flask B:
Since the pressure in flask A is given as 97.7 kPa, we can calculate the pressure of gas in flask B by subtracting the pressure difference from the pressure in flask A.
Pressure of gas in flask B = Pressure of gas in flask A - Pressure difference
Pressure of gas in flask B = 97.7 kPa - 6.1117 kPa
Pressure of gas in flask B = 91.5883 kPa
Conclusion:
The pressure of the gas in flask B is 91.5883 kPa.
- Density of oil: 0.847 g/cc
- Height of oil in flask A: 74 cm higher than the oil in flask B
- Pressure of gas in flask A: 97.7 kPa
To find:
- Pressure of gas in flask B
Assumptions:
- The density of the oil remains constant throughout the experiment.
- The height difference between the oil levels is the only factor affecting the pressure difference.
Explanation:
1. Understanding Manometer:
A manometer is a device used to measure the pressure of a gas. It consists of a U-shaped tube filled with a liquid, in this case, oil. The pressure difference between the two arms of the manometer is determined by the height difference of the liquid in the arms.
2. Pressure Difference in the Manometer:
The pressure difference between the two arms of the manometer is given by the formula:
ΔP = ρgh
Where:
- ΔP is the pressure difference
- ρ is the density of the liquid (oil)
- g is the acceleration due to gravity
- h is the height difference between the liquid levels in the two arms
3. Calculating Pressure of Gas in Flask B:
In this case, the height difference between the oil levels in flask A and flask B is given as 74 cm. Using the formula for pressure difference, we can calculate the pressure of gas in flask B.
ΔP = ρgh
Let's calculate the pressure difference:
ΔP = (0.847 g/cc) * (9.8 m/s^2) * (0.74 m)
ΔP = 6.1117 kPa
4. Pressure of Gas in Flask B:
Since the pressure in flask A is given as 97.7 kPa, we can calculate the pressure of gas in flask B by subtracting the pressure difference from the pressure in flask A.
Pressure of gas in flask B = Pressure of gas in flask A - Pressure difference
Pressure of gas in flask B = 97.7 kPa - 6.1117 kPa
Pressure of gas in flask B = 91.5883 kPa
Conclusion:
The pressure of the gas in flask B is 91.5883 kPa.
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A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B?
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A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B?.
A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B?.
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A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B?, a detailed solution for A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? has been provided alongside types of A manometer connected 2 flasks contains an oil density 0.847g/cc .The oil arm connected to flask A is 74cm higher than the oil in the arm connected to flask B. The gas in flask A has a pressure of 97.7 kpa. What is the pressure of gas in B? theory, EduRev gives you an
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