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On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled with
mercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth
(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)?
mercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth
(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)?
Most Upvoted Answer
On a planet where gplanet = 0.2gearth. What will be the difference in ...
Introduction:
In this scenario, we are given that the acceleration due to gravity (g) on a particular planet is 0.2 times the acceleration due to gravity on Earth (gearth). We need to determine the difference in the height of a column filled with mercury in a closed-end manometer when the gas inside is filled with a pressure of 2 atm on Earth.
Explanation:
To solve this problem, we can use the equation for pressure in a manometer:
P1 + ρgh1 = P2 + ρgh2
where P1 and P2 are the pressures on either side of the manometer, ρ is the density of the mercury, g is the acceleration due to gravity, and h1 and h2 are the heights of the mercury columns on each side of the manometer.
Step 1: Calculate the pressure difference:
The pressure difference (ΔP) between the gas inside the manometer and the outside atmosphere is given by:
ΔP = Pgas - Poutside
Since we are given that the gas is filled with a pressure of 2 atm on Earth and the outside pressure is 1 atm on both planets, the pressure difference is:
ΔP = 2 atm - 1 atm = 1 atm
Step 2: Determine the density of mercury:
The density of mercury (ρ) is a constant value and can be obtained from reference tables. Let's assume the density of mercury is 13.6 g/cm³.
Step 3: Calculate the height difference:
Using the equation for pressure in the manometer, we can rearrange it to solve for the height difference (Δh):
Δh = (Pgas - Poutside) / (ρg)
Substituting the known values, we have:
Δh = (1 atm) / (13.6 g/cm³ * 9.8 m/s² * 100 cm/m)
Simplifying the units, we get:
Δh = (1 * 101325 Pa) / (13.6 * 9.8 * 1000 kg/m³ * 9.8 m/s²)
Calculating the numerical value, we find:
Δh ≈ 0.075 m
Conclusion:
The difference in the height of the column filled with mercury in the closed-end manometer when the gas is filled with a pressure of 2 atm on Earth is approximately 0.075 meters.
In this scenario, we are given that the acceleration due to gravity (g) on a particular planet is 0.2 times the acceleration due to gravity on Earth (gearth). We need to determine the difference in the height of a column filled with mercury in a closed-end manometer when the gas inside is filled with a pressure of 2 atm on Earth.
Explanation:
To solve this problem, we can use the equation for pressure in a manometer:
P1 + ρgh1 = P2 + ρgh2
where P1 and P2 are the pressures on either side of the manometer, ρ is the density of the mercury, g is the acceleration due to gravity, and h1 and h2 are the heights of the mercury columns on each side of the manometer.
Step 1: Calculate the pressure difference:
The pressure difference (ΔP) between the gas inside the manometer and the outside atmosphere is given by:
ΔP = Pgas - Poutside
Since we are given that the gas is filled with a pressure of 2 atm on Earth and the outside pressure is 1 atm on both planets, the pressure difference is:
ΔP = 2 atm - 1 atm = 1 atm
Step 2: Determine the density of mercury:
The density of mercury (ρ) is a constant value and can be obtained from reference tables. Let's assume the density of mercury is 13.6 g/cm³.
Step 3: Calculate the height difference:
Using the equation for pressure in the manometer, we can rearrange it to solve for the height difference (Δh):
Δh = (Pgas - Poutside) / (ρg)
Substituting the known values, we have:
Δh = (1 atm) / (13.6 g/cm³ * 9.8 m/s² * 100 cm/m)
Simplifying the units, we get:
Δh = (1 * 101325 Pa) / (13.6 * 9.8 * 1000 kg/m³ * 9.8 m/s²)
Calculating the numerical value, we find:
Δh ≈ 0.075 m
Conclusion:
The difference in the height of the column filled with mercury in the closed-end manometer when the gas is filled with a pressure of 2 atm on Earth is approximately 0.075 meters.
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On a planet where gplanet = 0.2gearth. What will be the difference in ...
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On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)?
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On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)?.
On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a planet where gplanet = 0.2gearth. What will be the difference in the height of column filled withmercury in a closed end manometer when the gas is filled with the pressure of 2 atm on earth(Assuming : outside pressure to be 1 atm on both planet ; Volume of gas remain constant)?.
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