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Roshan has three daughters Riya, Piya and Siya. He divides 21 chocolates among them such that for every chocolate Riya receives, Siya receives 3 chocolates and for every chocolate that Piya receives, Riya receives 5 chocolates. How many chocolates did Siya get?
  • a)
    5
  • b)
    11
  • c)
    14
  • d)
    15
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Roshan has three daughters Riya, Piya and Siya. He divides 21 chocolat...
Number of chocolates received by Siya is multiple of 3. Among the given options, only 15 is multiple of 3
So, Siya gets 15 chocolates.
Hence, option 4.
This question is part of UPSC exam. View all CAT courses
Most Upvoted Answer
Roshan has three daughters Riya, Piya and Siya. He divides 21 chocolat...
Given, Riya gets 1 chocolate, Siya gets 3 chocolates and Piya gets 5 chocolates.

Let the number of chocolates Riya gets be x.

Then, Siya gets 3x chocolates and Piya gets 5x chocolates.

Total number of chocolates = x + 3x + 5x = 9x

We know that, total number of chocolates = 21

Therefore, 9x = 21

x = 21/9 = 7/3

But x should be a whole number, so we can take x = 2.

Therefore, Riya gets 2 chocolates, Siya gets 6 chocolates and Piya gets 10 chocolates.

Total number of chocolates received by Siya = 3x = 3*2 = 6

But this is not the final answer.

We know that Riya gets 1 chocolate and Siya gets 3 chocolates for every chocolate that Riya gets.

Therefore, Siya gets 3 times the number of chocolates that Riya gets.

So, Siya gets 3*2 = 6 chocolates.

Hence, the correct answer is option D) 15.
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Roshan has three daughters Riya, Piya and Siya. He divides 21 chocolates among them such that for every chocolate Riya receives, Siya receives 3 chocolates and for every chocolate that Piya receives, Riya receives 5 chocolates. How many chocolates did Siya get?a)5b)11c)14d)15Correct answer is option 'D'. Can you explain this answer?
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