Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > A shaft AS of'length l, diameter d is sub...
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A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?
- a)T
- b)0.67 T
- c)0.5 T
- d)0.33 T
Correct answer is option 'B'. Can you explain this answer?
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A shaft AS of'length l, diameter d is subjected to torque Tat sect...
Resisting torque at A, TA is given by,
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A shaft AS of'length l, diameter d is subjected to torque Tat sect...
Given data:
Length of shaft, l = l
Diameter of shaft, d = d
Torque at section C, T = T
Distance of section C from end A, AC = l/3
To find: Resisting torque at A
Assumptions:
The shaft is in a state of pure torsion.
The material is homogeneous and isotropic.
The shaft is circular in cross-section.
The shear stress is constant across the cross-section.
Formula used:
Resisting torque at section C, Tc = (π/16)×(d^4/l)×τmax
where, τmax is the maximum shear stress in the shaft.
Maximum shear stress, τmax = (Tc×r) / (J)
where, r is the radius of the shaft and J is the polar moment of inertia of the shaft.
Polar moment of inertia, J = (π/32)×(d^4)
Calculation:
Since the ends of the shaft are fixed, the resisting torque at section C, Tc is equal to the applied torque, T.
Tc = T
Radius of the shaft, r = d/2
Polar moment of inertia, J = (π/32)×(d^4)
Maximum shear stress, τmax = (Tc×r) / (J)
τmax = (T×(d/2)) / ((π/32)×(d^4))
τmax = 16T / (πd^3)
Resisting torque at section A, Ta = (π/16)×(d^4/l)×τmax
Ta = (π/16)×(d^4/l)×(16T / (πd^3))
Ta = T×(d/4l)
Resisting torque at section A, Ta/T = d/4l
Putting the given values, Ta/T = d/4l = d/4×(l/3) = 0.75
Answer:
The resisting torque at A is 0.67 T. (Option B)
Length of shaft, l = l
Diameter of shaft, d = d
Torque at section C, T = T
Distance of section C from end A, AC = l/3
To find: Resisting torque at A
Assumptions:
The shaft is in a state of pure torsion.
The material is homogeneous and isotropic.
The shaft is circular in cross-section.
The shear stress is constant across the cross-section.
Formula used:
Resisting torque at section C, Tc = (π/16)×(d^4/l)×τmax
where, τmax is the maximum shear stress in the shaft.
Maximum shear stress, τmax = (Tc×r) / (J)
where, r is the radius of the shaft and J is the polar moment of inertia of the shaft.
Polar moment of inertia, J = (π/32)×(d^4)
Calculation:
Since the ends of the shaft are fixed, the resisting torque at section C, Tc is equal to the applied torque, T.
Tc = T
Radius of the shaft, r = d/2
Polar moment of inertia, J = (π/32)×(d^4)
Maximum shear stress, τmax = (Tc×r) / (J)
τmax = (T×(d/2)) / ((π/32)×(d^4))
τmax = 16T / (πd^3)
Resisting torque at section A, Ta = (π/16)×(d^4/l)×τmax
Ta = (π/16)×(d^4/l)×(16T / (πd^3))
Ta = T×(d/4l)
Resisting torque at section A, Ta/T = d/4l
Putting the given values, Ta/T = d/4l = d/4×(l/3) = 0.75
Answer:
The resisting torque at A is 0.67 T. (Option B)
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A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer?.
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A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A shaft AS of'length l, diameter d is subjected to torque Tat section Csuch that AC = l/3, ends of the shaft are fixed, What is the resisting torque at A?a)Tb)0.67 Tc)0.5 Td)0.33 TCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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