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A large concrete slab 1 m thick has one dimensional temperature distribution:
T = 4 - 10x + 20x2 + 10x3
where T is temperature and x is distance from one face towards other face of wail. If the slab material has thermal diffusivity of 2 x 10-3m2/hr, what is the rate of change of temperature at the other face of the wall?
  • a)
    0.1°C/h
  • b)
    0.2°C/h
  • c)
    0.3°C/h
  • d)
    0.4°C/h
Correct answer is option 'B'. Can you explain this answer?
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To find the rate of change of temperature at the other face of the wall, we need to differentiate the temperature function with respect to x and evaluate it at the other face (x = 1).

Differentiating the temperature function, we get:

dT/dx = -10 - 40x + 30x^2

Now, we can substitute x = 1 into the derivative to find the rate of change of temperature at the other face:

dT/dx = -10 - 40(1) + 30(1)^2
= -10 - 40 + 30
= -20

Therefore, the rate of change of temperature at the other face of the wall is -20 degrees per meter.
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A large concrete slab 1 m thick has one dimensional temperature distribution:T = 4 - 10x + 20x2 + 10x3where T is temperature and x is distance from one face towards other face of wail. If the slab material has thermal diffusivity of 2 x 10-3m2/hr, what is the rate of change of temperature at the other face of the wall?a)0.1°C/hb)0.2°C/hc)0.3°C/hd)0.4°C/hCorrect answer is option 'B'. Can you explain this answer?
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