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Haemolytic jaundice is due to dominant gene but only 20% of the people develop this disease. A heterozygous man marries a homozygous normal woman. What proportion of the children in population would be expected to have this disorder:-
  • a)
    1/5
  • b)
    1/20
  • c)
    1/10
  • d)
    1/2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Haemolytic jaundice is due to dominant gene but only 20% of the people...
Haemolytic jaundice is a genetic disorder that is caused by a dominant gene. However, not everyone who carries this gene will develop the disease. In fact, only 20% of people with the gene will actually show symptoms of the disorder.

In this scenario, a heterozygous man (carrying one copy of the dominant gene) marries a homozygous normal woman (not carrying the gene at all). To determine the proportion of children in the population that would be expected to have this disorder, we need to consider the genetic possibilities of the offspring.

- First, let's determine the genotype of the parents:
- Heterozygous man: Hh (carries one copy of the dominant gene)
- Homozygous normal woman: hh (does not carry the gene)

- Now, let's consider the possible genotypes of the offspring:
- 50% chance of inheriting the dominant gene from the father (Hh)
- 50% chance of inheriting the normal gene from the mother (hh)

- Since the dominant gene causes the disorder, only those with the genotype Hh will be affected. Therefore, the proportion of children expected to have the disorder is:
- 50% (chance of inheriting the dominant gene) * 20% (chance of developing the disorder) = 10%

Thus, the correct answer is option 'c' - 1/10. Approximately 1 in 10 children in the population would be expected to have this disorder.
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