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The time complexity of the following C function
is (assume n > 0)
int recursive (int n)
{
if (n == 1)
return(1);
else
return(recursive(n- 1) + recursive(n - 1));
}
is (assume n > 0)
int recursive (int n)
{
if (n == 1)
return(1);
else
return(recursive(n- 1) + recursive(n - 1));
}
- a)O(n)
- b)O(n logo)
- c)O (n2)
- d)O(2n)
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The time complexity of the following C functionis (assume n > 0)int...
The given C function is recursive. The best way to find the time complexity of recursive function is that convert the code (algorithm) into recursion equation and solution of the recursion equation is the time complexity of given algorithm.
1. int recursive (int i){
2 . if ( n == 1) return (1);
3. else
4. return (recursive(n-1) + recursive(n-1));
5. }
Let recursive(n) - T(n)
According to line 2 if (n = = 1) return(1) then the recursive equation is
T(n) = 1, n = 1
According to line 4 the recursion equation is
T(n) = T ( n - 1 ) + T(n-1), n > 1
So the complete recursion equation is
2 . if ( n == 1) return (1);
3. else
4. return (recursive(n-1) + recursive(n-1));
5. }
Let recursive(n) - T(n)
According to line 2 if (n = = 1) return(1) then the recursive equation is
T(n) = 1, n = 1
According to line 4 the recursion equation is
T(n) = T ( n - 1 ) + T(n-1), n > 1
So the complete recursion equation is
Most Upvoted Answer
The time complexity of the following C functionis (assume n > 0)int...
The time complexity of the function can be determined by analyzing the number of iterations in the for loop.
The for loop runs from i = 1 to n, incrementing i by 2 at each iteration. This means that the loop will run n/2 times.
Inside the loop, there is a single statement that takes constant time to execute.
Therefore, the time complexity of the function is O(n/2), which simplifies to O(n).
The for loop runs from i = 1 to n, incrementing i by 2 at each iteration. This means that the loop will run n/2 times.
Inside the loop, there is a single statement that takes constant time to execute.
Therefore, the time complexity of the function is O(n/2), which simplifies to O(n).
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