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In NMR spectroscopy the product the nuclear ‘g’ factor (gN), the nuclear magneton (βN) and the magnetic field strength (B0) gives the:
- a)Energy of transition from α to β state
- b)Chemical shift
- c)Spin–Spin coupling constant
- d)Magnetogyric ratio
Correct answer is option 'A'. Can you explain this answer?
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In NMR spectroscopy the product the nuclear ‘g’ factor (gN...
-Nuclear magnetic resonance spectroscopy, most commonly known as NMR spectroscopy or magnetic resonance spectroscopy (MRS), is a spectroscopic technique to observe local magnetic fields around atomic nuclei.
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-The alignment (polarization) of the magnetic nuclear spins in an applied, constant magnetic field B0.
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In NMR spectroscopy the product the nuclear ‘g’ factor (gN), the nuclear magneton (βN) and the magnetic field strength (B0) gives the e
nergy of transition from α to β stateMost Upvoted Answer
In NMR spectroscopy the product the nuclear ‘g’ factor (gN...
Energy of transition from |m1> to |m2> state
In NMR spectroscopy, the energy of transition from one nuclear spin state to another is given by the product of the nuclear g factor (gN), the nuclear magneton (N), and the magnetic field strength (B0).
The nuclear g factor (gN) is a dimensionless parameter that describes the interaction of the nuclear magnetic moment with the magnetic field. It depends on the specific nucleus being studied and can be experimentally determined.
The nuclear magneton (N) is a physical constant that represents the magnetic moment of a single proton or neutron. It is defined as the Bohr magneton divided by the mass of the nucleon.
The magnetic field strength (B0) is the main magnetic field applied in the NMR experiment. It is typically generated by a superconducting magnet and is measured in Tesla (T).
When a nucleus with a non-zero spin is placed in a magnetic field, it can exist in different energy states depending on the orientation of its spin. These energy states are characterized by quantum numbers, such as m1 and m2.
The energy of transition from the m1 state to the m2 state is given by the equation:
ΔE = gN * N * B0 * (m2 - m1)
where ΔE is the energy difference between the two states.
Explanation:
- The energy of transition between nuclear spin states in NMR spectroscopy is determined by the product of the nuclear g factor, the nuclear magneton, and the magnetic field strength.
- The nuclear g factor describes the interaction of the nuclear magnetic moment with the magnetic field and is specific to the nucleus being studied.
- The nuclear magneton represents the magnetic moment of a single proton or neutron.
- The magnetic field strength is the main magnetic field applied in the NMR experiment and is typically generated by a superconducting magnet.
- The energy of transition is given by the equation ΔE = gN * N * B0 * (m2 - m1), where ΔE is the energy difference between the two states and m1 and m2 are the quantum numbers representing the orientations of the nuclear spin.
In NMR spectroscopy, the energy of transition from one nuclear spin state to another is given by the product of the nuclear g factor (gN), the nuclear magneton (N), and the magnetic field strength (B0).
The nuclear g factor (gN) is a dimensionless parameter that describes the interaction of the nuclear magnetic moment with the magnetic field. It depends on the specific nucleus being studied and can be experimentally determined.
The nuclear magneton (N) is a physical constant that represents the magnetic moment of a single proton or neutron. It is defined as the Bohr magneton divided by the mass of the nucleon.
The magnetic field strength (B0) is the main magnetic field applied in the NMR experiment. It is typically generated by a superconducting magnet and is measured in Tesla (T).
When a nucleus with a non-zero spin is placed in a magnetic field, it can exist in different energy states depending on the orientation of its spin. These energy states are characterized by quantum numbers, such as m1 and m2.
The energy of transition from the m1 state to the m2 state is given by the equation:
ΔE = gN * N * B0 * (m2 - m1)
where ΔE is the energy difference between the two states.
Explanation:
- The energy of transition between nuclear spin states in NMR spectroscopy is determined by the product of the nuclear g factor, the nuclear magneton, and the magnetic field strength.
- The nuclear g factor describes the interaction of the nuclear magnetic moment with the magnetic field and is specific to the nucleus being studied.
- The nuclear magneton represents the magnetic moment of a single proton or neutron.
- The magnetic field strength is the main magnetic field applied in the NMR experiment and is typically generated by a superconducting magnet.
- The energy of transition is given by the equation ΔE = gN * N * B0 * (m2 - m1), where ΔE is the energy difference between the two states and m1 and m2 are the quantum numbers representing the orientations of the nuclear spin.
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In NMR spectroscopy the product the nuclear ‘g’ factor (gN), the nuclear magneton (βN) and the magnetic field strength (B0) gives the:a)Energy of transition from α to β stateb)Chemical shiftc)Spin–Spin coupling constantd)Magnetogyric ratioCorrect answer is option 'A'. Can you explain this answer?
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