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JEE Exam  >  JEE Questions  >  The self induced emf of a coil is 25 volts. W... Start Learning for Free
The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is:
  • a)
    437.5 J
  • b)
    637.5 J
  • c)
    740 J
  • d)
    540 J
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The self induced emf of a coil is 25 volts. When the current in it is ...
Given:
Self-induced emf of the coil (e) = 25 volts
Initial current (I1) = 10 A
Final current (I2) = 25 A
Time taken (t) = 1 s

To find:
Change in the energy of the inductance (∆E)

Formula:
The self-induced emf (e) is given by the equation:
e = ∆E/∆t

Where:
∆E is the change in energy
∆t is the change in time

Calculation:
We know that the self-induced emf (e) is given by the equation:
e = ∆E/∆t

Rearranging the equation, we have:
∆E = e * ∆t

Substituting the given values:
∆E = 25 * 1
∆E = 25 J

Therefore, the change in the energy of the inductance (∆E) is 25 J.

Answer:
The correct option is (A) 437.5 J.
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Community Answer
The self induced emf of a coil is 25 volts. When the current in it is ...
|E|=-Ldi/dt ,25=L(25-10)/1,L=5/3H,U=1/2Li^2=1/2×5/3(25^2-10^2)=437.5J
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The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is:a)437.5 Jb)637.5 Jc)740 Jd)540 JCorrect answer is option 'A'. Can you explain this answer?
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The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is:a)437.5 Jb)637.5 Jc)740 Jd)540 JCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is:a)437.5 Jb)637.5 Jc)740 Jd)540 JCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is:a)437.5 Jb)637.5 Jc)740 Jd)540 JCorrect answer is option 'A'. Can you explain this answer?.
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