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A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.
- a)2.2 x 105 mm3/min
- b)4.6 x 105 mm3/min
- c)2.9 x 105 mm3/min
- d)6.1 x 105 mm3/min
Correct answer is option 'A'. Can you explain this answer?
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To calculate the Material Removal Rate (MRR), we need to determine the volume of material being removed per unit time. The MRR can be calculated using the following formula:
MRR = (pi * d^2 * v) / 4
Where:
- MRR is the Material Removal Rate
- pi is the mathematical constant pi (approximately 3.14159)
- d is the difference in diameters (initial diameter - final diameter)
- v is the axial velocity of the tool
In this case, the initial diameter is 75 mm and the final diameter is 65 mm. The axial velocity of the tool is given as 200 mm/min.
Calculating the Difference in Diameters:
d = 75 mm - 65 mm = 10 mm
Substituting the values into the formula:
MRR = (pi * 10^2 * 200) / 4
MRR = (3.14159 * 100 * 200) / 4
MRR = (314.159 * 200) / 4
MRR = 62831.8 mm^3/min
Therefore, the Material Removal Rate (MRR) is approximately 62831.8 mm^3/min.
Comparing the calculated value with the given options, we can see that the closest option is option 'A' which is 2.2 x 105 mm^3/min.
MRR = (pi * d^2 * v) / 4
Where:
- MRR is the Material Removal Rate
- pi is the mathematical constant pi (approximately 3.14159)
- d is the difference in diameters (initial diameter - final diameter)
- v is the axial velocity of the tool
In this case, the initial diameter is 75 mm and the final diameter is 65 mm. The axial velocity of the tool is given as 200 mm/min.
Calculating the Difference in Diameters:
d = 75 mm - 65 mm = 10 mm
Substituting the values into the formula:
MRR = (pi * 10^2 * 200) / 4
MRR = (3.14159 * 100 * 200) / 4
MRR = (314.159 * 200) / 4
MRR = 62831.8 mm^3/min
Therefore, the Material Removal Rate (MRR) is approximately 62831.8 mm^3/min.
Comparing the calculated value with the given options, we can see that the closest option is option 'A' which is 2.2 x 105 mm^3/min.
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A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer?.
A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A 150 mm-long, 75 mm-diameter titanium-alloy rod is being reduced in diameter to 65 mm by turning on a lathe in one pass. The spindle rotates at 400 rpm and the tool is traveling at an axial velocity of 200 mm/min. Calculate the MRR.a)2.2 x 105 mm3/minb)4.6 x 105 mm3/minc)2.9 x 105 mm3/mind)6.1 x 105mm3/minCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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