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A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :
[1 eV = 1.6 × 10–19J]
  • a)
    1010 and 5 eV
  • b)
    1014 and 10 eV
  • c)
    1012 and 5 eV
  • d)
    1011 and 5 eV
Correct answer is option 'D'. Can you explain this answer?
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A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer?
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A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer?.
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