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A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam.
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Here you can find the meaning of A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :[1 eV = 1.6 × 10–19J]a)1010 and 5 eVb)1014 and 10 eVc)1012 and 5 eVd)1011 and 5 eVCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.