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A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ = 310 nm. It falls normally on a metal (work function ϕ = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x is
Correct answer is '11'. Can you explain this answer?
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A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm...
Energy in 1 second = 6.4 × 10-5 × 1 × 1 = 6.4 × 10-5 Joule
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A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm...
To calculate the intensity of an electromagnetic beam, we need to know the power of the beam and the area over which the power is spread.
The formula for intensity is given by:
Intensity = Power / Area
Since we only have the intensity and want to find the power, we rearrange the formula as:
Power = Intensity * Area
Given that the intensity is 6.4 W/m^2, we need to find the area over which the power is spread.
If we assume that the beam is evenly distributed over a circular area, we can use the formula for the area of a circle:
Area = π * radius^2
However, we do not have the radius of the beam. Without additional information, it is not possible to calculate the power of the electromagnetic beam.
The formula for intensity is given by:
Intensity = Power / Area
Since we only have the intensity and want to find the power, we rearrange the formula as:
Power = Intensity * Area
Given that the intensity is 6.4 W/m^2, we need to find the area over which the power is spread.
If we assume that the beam is evenly distributed over a circular area, we can use the formula for the area of a circle:
Area = π * radius^2
However, we do not have the radius of the beam. Without additional information, it is not possible to calculate the power of the electromagnetic beam.
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A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?
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A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?.
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?.
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ample number of questions to practice A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? tests, examples and also practice JEE tests.
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