JEE Exam > JEE Questions > A beam of electromagnetic radiation of intens...
Start Learning for Free
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ = 310 nm. It falls normally on a metal (work function ϕ = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x is
Correct answer is '11'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm...
Energy in 1 second = 6.4 × 10-5 × 1 × 1 = 6.4 × 10-5 Joule
Free Test
FREE
| Start Free Test |
Community Answer
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm...
To calculate the intensity of an electromagnetic beam, we need to know the power of the beam and the area over which the power is spread.
The formula for intensity is given by:
Intensity = Power / Area
Since we only have the intensity and want to find the power, we rearrange the formula as:
Power = Intensity * Area
Given that the intensity is 6.4 W/m^2, we need to find the area over which the power is spread.
If we assume that the beam is evenly distributed over a circular area, we can use the formula for the area of a circle:
Area = π * radius^2
However, we do not have the radius of the beam. Without additional information, it is not possible to calculate the power of the electromagnetic beam.
The formula for intensity is given by:
Intensity = Power / Area
Since we only have the intensity and want to find the power, we rearrange the formula as:
Power = Intensity * Area
Given that the intensity is 6.4 W/m^2, we need to find the area over which the power is spread.
If we assume that the beam is evenly distributed over a circular area, we can use the formula for the area of a circle:
Area = π * radius^2
However, we do not have the radius of the beam. Without additional information, it is not possible to calculate the power of the electromagnetic beam.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?
Question Description
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?.
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?.
Solutions for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer?, a detailed solution for A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? has been provided alongside types of A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A beam of electromagnetic radiation of intensity 6.4 × 10-5 W/cm2 is comprised of wavelength, λ= 310 nm. It falls normally on a metal (work function = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, then total number of electrons ejected in 1s is 10x. (hc = 1,240 eVnm, 1 eV = 1.6 × 10-19 J). Then, x isCorrect answer is '11'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup