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The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) side
- a)(0.02 + j 0.07)Ω
- b)(0.55 + j 1.925)Ω
- c)(42 + j 147)Ω
- d)(72.6 + j 254.1)Ω
Correct answer is option 'D'. Can you explain this answer?
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Circuit is a measure of its opposition to the flow of alternating current. It is represented by the symbol Z and is a complex quantity, meaning it has both a magnitude and a phase angle.
The magnitude of impedance is given by the formula |Z| = √(R^2 + X^2), where R is the resistance of the circuit and X is the reactance. The reactance can be either capacitive or inductive, depending on the components in the circuit.
The phase angle of impedance is given by the formula θ = arctan(X/R), where θ is the phase angle in radians. The phase angle represents the phase shift between the voltage and current in the circuit.
The impedance of a circuit can be calculated using Ohm's law, which states that V = IZ, where V is the voltage across the circuit, I is the current flowing through the circuit, and Z is the impedance.
In summary, the impedance of a circuit is a complex quantity that represents the opposition to the flow of alternating current. It is determined by the resistance and reactance of the circuit and can be calculated using Ohm's law.
The magnitude of impedance is given by the formula |Z| = √(R^2 + X^2), where R is the resistance of the circuit and X is the reactance. The reactance can be either capacitive or inductive, depending on the components in the circuit.
The phase angle of impedance is given by the formula θ = arctan(X/R), where θ is the phase angle in radians. The phase angle represents the phase shift between the voltage and current in the circuit.
The impedance of a circuit can be calculated using Ohm's law, which states that V = IZ, where V is the voltage across the circuit, I is the current flowing through the circuit, and Z is the impedance.
In summary, the impedance of a circuit is a complex quantity that represents the opposition to the flow of alternating current. It is determined by the resistance and reactance of the circuit and can be calculated using Ohm's law.
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The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer?
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The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer?.
The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer?.
Solutions for The impedance of a Δ- Y 11000/400V 3-ΔT/F of capacity 100 KVA as on its name plate as z = (0.02 + j0.07) pu. The ohmic impedance in Ωreferred to primary (11000 V) sidea)(0.02 + j 0.07)Ωb)(0.55 + j 1.925)Ωc)(42 + j 147)Ωd)(72.6 + j 254.1)ΩCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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