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Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.
(Round off to 2 decimal places)
(Round off to 2 decimal places)
Correct answer is between '54.67,54.71'. Can you explain this answer?
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Light of wavelength 680 nm is incident normally on a diffraction grati...
Concept: Diffraction Grating
When a wave encounters an obstacle, it spreads out in different directions. This phenomenon is called diffraction. Diffraction grating is a device that consists of a large number of parallel and equally spaced slits. When light passes through a diffraction grating, it diffracts and the diffracted waves interfere with each other. This interference results in a pattern of bright and dark fringes. The angle at which a bright fringe is observed is given by:
sin θ = mλ/d
where θ is the angle of diffraction, m is the order of the bright fringe, λ is the wavelength of light and d is the distance between the slits.
Given:
Wavelength of light, λ = 680 nm
Number of lines per cm, N = 4000 lines/cm
Distance between the lines, d = 1/N = 0.00025 cm
Order of maximum, m = 3
Solution:
We can use the formula for the angle of diffraction to calculate the angle for the third-order maximum.
sin θ = mλ/d
sin θ = 3 × 680 × 10^-9 / 0.00025
sin θ = 0.816
θ = sin^-1(0.816)
θ = 54.70 degrees
Therefore, the diffraction angle corresponding to the third-order maximum is 54.70 degrees.
Answer:
The diffraction angle corresponding to the third-order maximum is 54.70 degrees. (Rounded off to 2 decimal places, the answer is between 54.67 and 54.71 degrees).
When a wave encounters an obstacle, it spreads out in different directions. This phenomenon is called diffraction. Diffraction grating is a device that consists of a large number of parallel and equally spaced slits. When light passes through a diffraction grating, it diffracts and the diffracted waves interfere with each other. This interference results in a pattern of bright and dark fringes. The angle at which a bright fringe is observed is given by:
sin θ = mλ/d
where θ is the angle of diffraction, m is the order of the bright fringe, λ is the wavelength of light and d is the distance between the slits.
Given:
Wavelength of light, λ = 680 nm
Number of lines per cm, N = 4000 lines/cm
Distance between the lines, d = 1/N = 0.00025 cm
Order of maximum, m = 3
Solution:
We can use the formula for the angle of diffraction to calculate the angle for the third-order maximum.
sin θ = mλ/d
sin θ = 3 × 680 × 10^-9 / 0.00025
sin θ = 0.816
θ = sin^-1(0.816)
θ = 54.70 degrees
Therefore, the diffraction angle corresponding to the third-order maximum is 54.70 degrees.
Answer:
The diffraction angle corresponding to the third-order maximum is 54.70 degrees. (Rounded off to 2 decimal places, the answer is between 54.67 and 54.71 degrees).
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Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer?
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Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer?.
Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light of wavelength 680 nm is incident normally on a diffraction grating having 4000 lines/cm. The diffraction angle (in degrees) corresponding to the third-order maximum is ________.(Round off to 2 decimal places)Correct answer is between '54.67,54.71'. Can you explain this answer?.
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