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Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :
- a)3F/4
- b)F/2
- c)3F/8
- d)F
Correct answer is option 'C'. Can you explain this answer?
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Two identical conducting spheres A and B carry equal charge. They are ...
when A and C are touched charge on both will be q/2Then when B and C are touched
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Two identical conducting spheres A and B carry equal charge. They are ...
Given:
- Two identical conducting spheres A and B carry equal charge.
- They are separated by a distance much larger than their diameters.
- The force between them is F.
- A third identical conducting sphere C is uncharged.
To find:
The force between A and B after sphere C is touched to A then to B and then removed.
Solution:
When sphere C is touched to sphere A, it acquires some charge by induction. The charge distribution on sphere A is redistributed due to the presence of the grounded sphere C. As a result, sphere A loses some charge to the ground and gains an equal amount of charge of opposite polarity from sphere C.
Similarly, when sphere C is touched to sphere B, it acquires some charge by induction. The charge distribution on sphere B is redistributed due to the presence of the grounded sphere C. As a result, sphere B loses some charge to the ground and gains an equal amount of charge of opposite polarity from sphere C.
After sphere C is removed, spheres A and B have acquired opposite charges due to the transfer of charge from sphere C. The magnitude of charges on spheres A and B remains the same as they were initially.
Now, let's analyze the forces between the spheres:
- Initially, when spheres A and B carry equal charge, the force between them is F.
- After sphere C is touched to sphere A, the force between A and B decreases because the induced charges on A and B are of opposite polarity, leading to a partial cancellation of the forces between them. Let this force be F1.
- After sphere C is touched to sphere B, the force between A and B decreases further due to the additional partial cancellation of forces between them by the induced charges. Let this force be F2.
The force between A and B after sphere C is removed is given by:
Force between A and B = F - F1 - F2
Since F1 and F2 are forces of attraction between the induced charges on spheres A and B, they are always positive. Therefore:
Force between A and B < />
Hence, the correct option is (c) 3F/8.
- Two identical conducting spheres A and B carry equal charge.
- They are separated by a distance much larger than their diameters.
- The force between them is F.
- A third identical conducting sphere C is uncharged.
To find:
The force between A and B after sphere C is touched to A then to B and then removed.
Solution:
When sphere C is touched to sphere A, it acquires some charge by induction. The charge distribution on sphere A is redistributed due to the presence of the grounded sphere C. As a result, sphere A loses some charge to the ground and gains an equal amount of charge of opposite polarity from sphere C.
Similarly, when sphere C is touched to sphere B, it acquires some charge by induction. The charge distribution on sphere B is redistributed due to the presence of the grounded sphere C. As a result, sphere B loses some charge to the ground and gains an equal amount of charge of opposite polarity from sphere C.
After sphere C is removed, spheres A and B have acquired opposite charges due to the transfer of charge from sphere C. The magnitude of charges on spheres A and B remains the same as they were initially.
Now, let's analyze the forces between the spheres:
- Initially, when spheres A and B carry equal charge, the force between them is F.
- After sphere C is touched to sphere A, the force between A and B decreases because the induced charges on A and B are of opposite polarity, leading to a partial cancellation of the forces between them. Let this force be F1.
- After sphere C is touched to sphere B, the force between A and B decreases further due to the additional partial cancellation of forces between them by the induced charges. Let this force be F2.
The force between A and B after sphere C is removed is given by:
Force between A and B = F - F1 - F2
Since F1 and F2 are forces of attraction between the induced charges on spheres A and B, they are always positive. Therefore:
Force between A and B < />
Hence, the correct option is (c) 3F/8.
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Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer?
Question Description
Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer?.
Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :a)3F/4b)F/2c)3F/8d)FCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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