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In a class of 100 students, 55 students have passed in Mathematics and 67 students have passed in Physics. Then, the number of student who have passed in Physics only, is
  • a)
    22
  • b)
    33
  • c)
    10
  • d)
    45
Correct answer is option 'D'. Can you explain this answer?
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In a class of 100 students, 55 students have passed in Mathematics and...
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In a class of 100 students, 55 students have passed in Mathematics and...
To solve this problem, let's break down the given information and use set theory concepts.

- Total number of students = 100
- Number of students who passed in Mathematics = 55
- Number of students who passed in Physics = 67

We need to find the number of students who passed in Physics only.

Let's assume the set M represents the students who passed in Mathematics and the set P represents the students who passed in Physics.

- Number of students who passed in Mathematics only = |M - P|
- Number of students who passed in Physics only = |P - M|

We know that the total number of students is 100, and the number of students who passed in Mathematics is 55. Therefore, the number of students who did not pass in Mathematics is 100 - 55 = 45.

Now, let's calculate the number of students who passed in Physics only.

|P - M| = |P| - |M|

We are given that |P| = 67 (number of students who passed in Physics), and |M| = 55 (number of students who passed in Mathematics).

|P - M| = 67 - 55 = 12

Therefore, the number of students who passed in Physics only is 12.

However, the options provided for the answer are not consistent with the calculations. The correct answer should be 12, not 45.
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In a class of 100 students, 55 students have passed in Mathematics and 67 students have passed in Physics. Then, the number of student who have passed in Physics only, isa)22b)33c)10d)45Correct answer is option 'D'. Can you explain this answer?
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