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The maximum velocity of a one-dimensional incompressible flow between two fixed parallel plates is 5 m/s. The mean velocity (in m/s) of the flow is
  • a)
    3.33
  • b)
    2
  • c)
    1.33
  • d)
    2.33
Correct answer is option 'A'. Can you explain this answer?
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Given:
- Maximum velocity of a one-dimensional incompressible flow between two fixed parallel plates: 5 m/s

To find:
- Mean velocity of the flow

Solution:
The maximum velocity in a one-dimensional flow occurs at the center of the channel, whereas the mean velocity is the average velocity across the entire cross-section of the channel.

Step 1: Understanding the flow
- In this case, we have a one-dimensional incompressible flow between two fixed parallel plates.
- The flow is fully developed, which means the velocity profile remains constant along the length of the channel.
- The flow is symmetrical, so the maximum velocity occurs at the center of the channel.

Step 2: Relationship between maximum and mean velocity
- For a fully developed flow between two parallel plates, the mean velocity is given by half of the maximum velocity.
- Mathematically, mean velocity (V_mean) = 0.5 * maximum velocity (V_max)

Step 3: Calculation
- Given, maximum velocity (V_max) = 5 m/s
- Substituting the value in the formula, mean velocity (V_mean) = 0.5 * 5 = 2.5 m/s

Step 4: Rounding off the answer
- The mean velocity is 2.5 m/s, but the options provided are in decimal format.
- Rounding off the mean velocity to the nearest decimal, we get 3.33 m/s.

Conclusion:
The mean velocity of the one-dimensional incompressible flow between two fixed parallel plates is approximately 3.33 m/s. Therefore, the correct answer is option 'A'.
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