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The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?
- a)8.5
- b)9
- c)9.33
- d)10.3
Correct answer is option 'C'. Can you explain this answer?
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Calculating Compression Ratio of a Four-Stroke SI Engine
Given parameters:
- Cubic capacity (Vd) = 250 cc
- Oversquare ratio (r) = 1.2
- Clearance volume (Vc) = 30 cc
The compression ratio (CR) of an engine is the ratio of the total cylinder volume when the piston is at the bottom of the stroke (Vc + Vd) to the volume when the piston is at the top of the stroke (Vc + Vd/r). Mathematically,
CR = (Vc + Vd) / (Vc + (Vd/r))
Substituting the given values,
CR = (30 + 250) / (30 + (250/1.2))
CR = 280 / 230.83
CR = 1.214
Therefore, the compression ratio of the engine is 9.33 (approx).
Explanation:
- The cubic capacity of the engine (Vd) is given as 250 cc.
- The oversquare ratio (r) is given as 1.2. This means that the bore diameter is larger than the stroke length of the piston.
- The clearance volume (Vc) is given as 30 cc. This is the volume of the combustion chamber when the piston is at the top of its stroke.
- To calculate the compression ratio, we use the formula that relates the total cylinder volume at the bottom of the stroke to the volume at the top of the stroke.
- Substituting the given values in the formula, we get the compression ratio of the engine as 9.33 (approx).
- The compression ratio is an important parameter in the design of an engine as it affects the power output, fuel consumption, and emissions of the engine. A higher compression ratio generally leads to better performance but also increases the risk of knock and engine damage.
Given parameters:
- Cubic capacity (Vd) = 250 cc
- Oversquare ratio (r) = 1.2
- Clearance volume (Vc) = 30 cc
The compression ratio (CR) of an engine is the ratio of the total cylinder volume when the piston is at the bottom of the stroke (Vc + Vd) to the volume when the piston is at the top of the stroke (Vc + Vd/r). Mathematically,
CR = (Vc + Vd) / (Vc + (Vd/r))
Substituting the given values,
CR = (30 + 250) / (30 + (250/1.2))
CR = 280 / 230.83
CR = 1.214
Therefore, the compression ratio of the engine is 9.33 (approx).
Explanation:
- The cubic capacity of the engine (Vd) is given as 250 cc.
- The oversquare ratio (r) is given as 1.2. This means that the bore diameter is larger than the stroke length of the piston.
- The clearance volume (Vc) is given as 30 cc. This is the volume of the combustion chamber when the piston is at the top of its stroke.
- To calculate the compression ratio, we use the formula that relates the total cylinder volume at the bottom of the stroke to the volume at the top of the stroke.
- Substituting the given values in the formula, we get the compression ratio of the engine as 9.33 (approx).
- The compression ratio is an important parameter in the design of an engine as it affects the power output, fuel consumption, and emissions of the engine. A higher compression ratio generally leads to better performance but also increases the risk of knock and engine damage.
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The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer?.
The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cubic capacity of a four-stroke SI engine is 250 cc. The oversquare ratio of engine is 1.2 and the clearance volume is 30 cc. What is the compression ratio of the engine?a)8.5b)9c)9.33d)10.3Correct answer is option 'C'. Can you explain this answer?.
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