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A journal 30 mm in diameter supported in sliding bearings has a maximum end reaction of 2500 N. What is the length of sliding bearing for an allowable bearing pressure of 5 N/mm2?
  • a)
    12 mm
  • b)
    14.67 mm
  • c)
    16.67 mm
  • d)
    19 mm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A journal30 mm in diameter supported in sliding bearings has a maximum...
Projected area,
A = l x d =30 l mm2
Bearing pressure,
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Most Upvoted Answer
A journal30 mm in diameter supported in sliding bearings has a maximum...
Given data:
Diameter of the journal = 30 mm
Maximum end reaction = 2500 N
Allowable bearing pressure = 5 N/mm2

To find:
Length of the sliding bearing

Formula:
Bearing pressure = (Force on the bearing) / (Area of the bearing)

Calculation:
1. Calculate the area of the bearing:
Area of the bearing = π × (Diameter of the journal) × (Length of the bearing)
⇒ Area of the bearing = π × (30 mm) × (Length of the bearing)

2. Substitute the given values:
5 N/mm2 = (2500 N) / [π × (30 mm) × (Length of the bearing)]

3. Solve for the length of the bearing:
Length of the bearing = (2500 N) / [5 N/mm2 × π × (30 mm)]
⇒ Length of the bearing = (2500 N) / [5 N/mm2 × 3.14 × 30 mm]
⇒ Length of the bearing ≈ 16.67 mm

Therefore, the length of the sliding bearing for an allowable bearing pressure of 5 N/mm2 is approximately 16.67 mm.
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A journal30 mm in diameter supported in sliding bearings has a maximum end reaction of 2500 N. What is the length of sliding bearing for an allowable bearing pressure of 5 N/mm2?a)12 mmb)14.67 mmc)16.67 mmd)19 mmCorrect answer is option 'C'. Can you explain this answer?
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