Mechanical Engineering Exam > Mechanical Engineering Questions > The load on the journal hearing is 150 kN du...
Start Learning for Free
The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.
What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)
Correct answer is '312.5'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The load on the journal hearing is 150 kN due to turbine shaft of 300...
Given:
- Load on the journal bearing = 150 kN
- Diameter of the turbine shaft = 300 mm
- Speed of the turbine shaft = 1800 rpm
- Allowable bearing pressure = 1.6 N/mm^2
To Find:
- Length of the bearing
Solution:
To calculate the length of the bearing, we need to determine the bearing area and then divide it by the allowable bearing pressure.
Step 1: Calculate the bearing area
The bearing area can be calculated using the formula:
A = π * d * L
Where:
- A is the bearing area
- d is the diameter of the journal
- L is the length of the bearing
We are given the diameter of the turbine shaft, which is 300 mm. We need to convert it to meters for further calculations.
d = 300 mm = 0.3 m
Substituting the values in the formula:
A = π * 0.3 * L
Step 2: Calculate the load on the bearing
The load on the bearing can be calculated using the formula:
Load = π * d * L * ω * ρ
Where:
- Load is the load on the bearing
- d is the diameter of the journal
- L is the length of the bearing
- ω is the angular velocity of the turbine shaft
- ρ is the density of the fluid in the bearing (assumed to be constant)
We are given the angular velocity of the turbine shaft, which is 1800 rpm. We need to convert it to radians per second for further calculations.
ω = 1800 rpm * (2π rad/rev) / (60 s/min) = 188.5 rad/s
Substituting the values in the formula:
150 kN = π * 0.3 * L * 188.5 * ρ
Step 3: Calculate the length of the bearing
Now we can solve the equation for the length of the bearing (L):
L = (150 kN) / (π * 0.3 * 188.5 * ρ)
To calculate the length of the bearing, we need the value of ρ (density of the fluid). However, this value is not provided in the given information. Without this value, we cannot calculate the length of the bearing accurately.
Therefore, it is not possible to determine the length of the bearing with the given information.
- Load on the journal bearing = 150 kN
- Diameter of the turbine shaft = 300 mm
- Speed of the turbine shaft = 1800 rpm
- Allowable bearing pressure = 1.6 N/mm^2
To Find:
- Length of the bearing
Solution:
To calculate the length of the bearing, we need to determine the bearing area and then divide it by the allowable bearing pressure.
Step 1: Calculate the bearing area
The bearing area can be calculated using the formula:
A = π * d * L
Where:
- A is the bearing area
- d is the diameter of the journal
- L is the length of the bearing
We are given the diameter of the turbine shaft, which is 300 mm. We need to convert it to meters for further calculations.
d = 300 mm = 0.3 m
Substituting the values in the formula:
A = π * 0.3 * L
Step 2: Calculate the load on the bearing
The load on the bearing can be calculated using the formula:
Load = π * d * L * ω * ρ
Where:
- Load is the load on the bearing
- d is the diameter of the journal
- L is the length of the bearing
- ω is the angular velocity of the turbine shaft
- ρ is the density of the fluid in the bearing (assumed to be constant)
We are given the angular velocity of the turbine shaft, which is 1800 rpm. We need to convert it to radians per second for further calculations.
ω = 1800 rpm * (2π rad/rev) / (60 s/min) = 188.5 rad/s
Substituting the values in the formula:
150 kN = π * 0.3 * L * 188.5 * ρ
Step 3: Calculate the length of the bearing
Now we can solve the equation for the length of the bearing (L):
L = (150 kN) / (π * 0.3 * 188.5 * ρ)
To calculate the length of the bearing, we need the value of ρ (density of the fluid). However, this value is not provided in the given information. Without this value, we cannot calculate the length of the bearing accurately.
Therefore, it is not possible to determine the length of the bearing with the given information.
Free Test
FREE
| Start Free Test |
Community Answer
The load on the journal hearing is 150 kN due to turbine shaft of 300...
The load on the journal bearing is 150 kN due to turbine shaft of 300mm diameter running at 1800 rpm. Determine the following: (K3-3) a. length of the bearing if the allowable bearing pressure is 1.6 N/mm2 , and b. amount of heat to be removed by the lubricant per minute if the bearing temperature is 600C and viscosity of the oil is 0.02kg/m-s and the bearing clearance is 0.25mm
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer?
Question Description
The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer?.
The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer?.
Solutions for The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer?, a detailed solution for The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? has been provided alongside types of The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The load on the journal hearing is 150 kN due to turbine shaft of 300 mm diameter running at 1800 r.p.m.What will be the length of the bearing if the allowable bearing pressure is 1.6 N/mm2?(Answer up to one decimal place)Correct answer is '312.5'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup