A cantilever beam of rectangular cross-section is 1 m deep and 0.6 m t...
Explanation:
To understand why the beam would be strengthened 0.6 times, we need to consider the moment of inertia of the beam.
The moment of inertia (I) of a rectangular cross-section beam is given by the equation:
I = (b * h^3) / 12
Where b is the breadth or thickness of the beam, and h is the depth of the beam.
Original Beam:
In the original beam, the breadth (b) is 0.6 m and the depth (h) is 1 m. Therefore, the moment of inertia (I1) can be calculated as:
I1 = (0.6 * 1^3) / 12 = 0.05 m^4
Modified Beam:
In the modified beam, the breadth (b) is 1 m and the depth (h) is 0.6 m. Therefore, the moment of inertia (I2) can be calculated as:
I2 = (1 * 0.6^3) / 12 = 0.036 m^4
Comparison:
To compare the strengths of the two beams, we can compare their moments of inertia. A higher moment of inertia indicates a stronger beam.
The ratio of the moment of inertia of the modified beam (I2) to the moment of inertia of the original beam (I1) can be calculated as:
Ratio = I2 / I1 = 0.036 / 0.05 = 0.72
Therefore, the modified beam is 0.72 times as strong as the original beam.
Conclusion:
Since the modified beam has a higher moment of inertia, it is stronger than the original beam. Thus, the correct answer is option 'C': the beam would be strengthened 0.6 times.