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Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).
Correct answer is '16.24'. Can you explain this answer?
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Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC ...
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Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC ...
Given data:
- Ambient air pressure: 100 kPa
- Dry bulb temperature: 30°C
- Relative humidity: 60%
- Saturation pressure of water at 30°C: 4.24 kPa
Calculating partial pressure of water vapor:
The partial pressure of water vapor can be determined using the relative humidity and saturation pressure of water at the given temperature.
Partial pressure of water vapor = Relative humidity × Saturation pressure of water
Partial pressure of water vapor = 0.60 × 4.24 kPa
Partial pressure of water vapor = 2.54 kPa
Calculating specific humidity:
Specific humidity is the ratio of the mass of water vapor to the mass of dry air in a given volume.
Specific humidity = (Mass of water vapor) / (Mass of dry air)
To calculate specific humidity, we need to find the mass of water vapor and the mass of dry air.
Calculating mass of water vapor:
The mass of water vapor can be determined using the ideal gas law.
PV = nRT
Where:
P = Pressure (in Pa)
V = Volume (in m³)
n = Number of moles
R = Ideal gas constant (8.314 J/(mol·K))
T = Temperature (in Kelvin)
Rearranging the equation, we get:
n = PV / RT
The number of moles of water vapor can be calculated using the partial pressure of water vapor and the ideal gas constant.
Number of moles of water vapor = (Partial pressure of water vapor) / (Ideal gas constant × Temperature in Kelvin)
Number of moles of water vapor = (2.54 kPa × 1000 Pa/kPa) / (8.314 J/(mol·K) × (30 + 273.15) K)
Number of moles of water vapor = 0.10 mol
To convert moles to grams, we need the molar mass of water vapor.
Molar mass of water vapor = 18.015 g/mol
Mass of water vapor = (Number of moles of water vapor) × (Molar mass of water vapor)
Mass of water vapor = 0.10 mol × 18.015 g/mol
Mass of water vapor = 1.80 g
Calculating mass of dry air:
The mass of dry air can be determined using the ideal gas law.
Number of moles of dry air = (Total pressure - Partial pressure of water vapor) / (Ideal gas constant × Temperature in Kelvin)
Number of moles of dry air = (100 kPa × 1000 Pa/kPa - 2.54 kPa × 1000 Pa/kPa) / (8.314 J/(mol·K) × (30 + 273.15) K)
Number of moles of dry air = 3.60 mol
To convert moles to grams, we need the molar mass of dry air.
Molar mass of dry air = 28.97 g/mol
Mass of dry air = (Number of moles of dry air) × (Molar mass of dry air)
Mass of dry air = 3.60 mol × 28.97 g/mol
Mass of dry air = 104.29 g
Calculating specific humidity:
Specific humidity =
- Ambient air pressure: 100 kPa
- Dry bulb temperature: 30°C
- Relative humidity: 60%
- Saturation pressure of water at 30°C: 4.24 kPa
Calculating partial pressure of water vapor:
The partial pressure of water vapor can be determined using the relative humidity and saturation pressure of water at the given temperature.
Partial pressure of water vapor = Relative humidity × Saturation pressure of water
Partial pressure of water vapor = 0.60 × 4.24 kPa
Partial pressure of water vapor = 2.54 kPa
Calculating specific humidity:
Specific humidity is the ratio of the mass of water vapor to the mass of dry air in a given volume.
Specific humidity = (Mass of water vapor) / (Mass of dry air)
To calculate specific humidity, we need to find the mass of water vapor and the mass of dry air.
Calculating mass of water vapor:
The mass of water vapor can be determined using the ideal gas law.
PV = nRT
Where:
P = Pressure (in Pa)
V = Volume (in m³)
n = Number of moles
R = Ideal gas constant (8.314 J/(mol·K))
T = Temperature (in Kelvin)
Rearranging the equation, we get:
n = PV / RT
The number of moles of water vapor can be calculated using the partial pressure of water vapor and the ideal gas constant.
Number of moles of water vapor = (Partial pressure of water vapor) / (Ideal gas constant × Temperature in Kelvin)
Number of moles of water vapor = (2.54 kPa × 1000 Pa/kPa) / (8.314 J/(mol·K) × (30 + 273.15) K)
Number of moles of water vapor = 0.10 mol
To convert moles to grams, we need the molar mass of water vapor.
Molar mass of water vapor = 18.015 g/mol
Mass of water vapor = (Number of moles of water vapor) × (Molar mass of water vapor)
Mass of water vapor = 0.10 mol × 18.015 g/mol
Mass of water vapor = 1.80 g
Calculating mass of dry air:
The mass of dry air can be determined using the ideal gas law.
Number of moles of dry air = (Total pressure - Partial pressure of water vapor) / (Ideal gas constant × Temperature in Kelvin)
Number of moles of dry air = (100 kPa × 1000 Pa/kPa - 2.54 kPa × 1000 Pa/kPa) / (8.314 J/(mol·K) × (30 + 273.15) K)
Number of moles of dry air = 3.60 mol
To convert moles to grams, we need the molar mass of dry air.
Molar mass of dry air = 28.97 g/mol
Mass of dry air = (Number of moles of dry air) × (Molar mass of dry air)
Mass of dry air = 3.60 mol × 28.97 g/mol
Mass of dry air = 104.29 g
Calculating specific humidity:
Specific humidity =
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Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer?
Question Description
Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer?.
Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer?.
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Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer?, a detailed solution for Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? has been provided alongside types of Ambient air is at a pressure of 100 kPa, dry bulb temperature of 30oC and 60% relative humidity. The saturation pressure of water at 30oC is 4.24 kPa. The specific humidity of air (in g/kg of dry air) is __________ (correct to two decimal places).Correct answer is '16.24'. Can you explain this answer? theory, EduRev gives you an
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