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A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:
- a)Cl-
- b)S2
- c)SO42-
- d)CO32-
Correct answer is option 'A'. Can you explain this answer?
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Explanation:
When a white sodium salt dissolves readily in water to give a solution that is neutral to litmus, it suggests that the salt is a neutral compound. In this case, the neutral compound is a sodium salt.
Precipitation Reaction:
When silver nitrate solution is added to the sodium salt solution, a white precipitate is obtained. The formation of a precipitate indicates a chemical reaction between the silver nitrate and the sodium salt. The precipitate formed is insoluble in dilute nitric acid.
Anion Identification:
To identify the anion present in the sodium salt, we need to consider the properties of the precipitate formed. In this case, the precipitate is white and insoluble in dilute nitric acid.
Chloride Ion:
- Chloride ions (Cl-) react with silver ions (Ag+) to form a white precipitate of silver chloride (AgCl).
- Silver chloride is insoluble in dilute nitric acid.
Sulfide Ion:
- Sulfide ions (S2-) react with silver ions (Ag+) to form a black precipitate of silver sulfide (Ag2S).
- Silver sulfide is insoluble in dilute nitric acid.
Sulfate Ion:
- Sulfate ions (SO42-) do not react with silver ions (Ag+) to form a precipitate.
- Therefore, sulfate ions can be ruled out as the anion.
Carbonate Ion:
- Carbonate ions (CO32-) react with silver ions (Ag+) to form a white precipitate of silver carbonate (Ag2CO3).
- However, silver carbonate is soluble in dilute nitric acid.
Conclusion:
Based on the observations, the anion present in the sodium salt is chloride (Cl-).
When a white sodium salt dissolves readily in water to give a solution that is neutral to litmus, it suggests that the salt is a neutral compound. In this case, the neutral compound is a sodium salt.
Precipitation Reaction:
When silver nitrate solution is added to the sodium salt solution, a white precipitate is obtained. The formation of a precipitate indicates a chemical reaction between the silver nitrate and the sodium salt. The precipitate formed is insoluble in dilute nitric acid.
Anion Identification:
To identify the anion present in the sodium salt, we need to consider the properties of the precipitate formed. In this case, the precipitate is white and insoluble in dilute nitric acid.
Chloride Ion:
- Chloride ions (Cl-) react with silver ions (Ag+) to form a white precipitate of silver chloride (AgCl).
- Silver chloride is insoluble in dilute nitric acid.
Sulfide Ion:
- Sulfide ions (S2-) react with silver ions (Ag+) to form a black precipitate of silver sulfide (Ag2S).
- Silver sulfide is insoluble in dilute nitric acid.
Sulfate Ion:
- Sulfate ions (SO42-) do not react with silver ions (Ag+) to form a precipitate.
- Therefore, sulfate ions can be ruled out as the anion.
Carbonate Ion:
- Carbonate ions (CO32-) react with silver ions (Ag+) to form a white precipitate of silver carbonate (Ag2CO3).
- However, silver carbonate is soluble in dilute nitric acid.
Conclusion:
Based on the observations, the anion present in the sodium salt is chloride (Cl-).
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A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer?
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A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer?.
A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer?.
Solutions for A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the aforementioned solution, a white precipitate is obtained which does not dissolve in dil. nitric acid. The anion is:a)Cl-b)S2c)SO42-d)CO32-Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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