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In a tensile testing experiment on a specimen of 1 cm2 area, the maximum load observed was 5 tonnes and neck area 0.25 cm2. The ultimate tensile strength of specimen is
- a)4 tonnes/cm2
- b)5 tonnes/cm2
- c)16 tonnes/cm2
- d)22 tonnes/cm2
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In a tensile testing experiment on a specimen of 1 cm2area, the maximu...
Ultimate tensile strength is corresponding to the maximum load and cross-sectional area of the specimen at the start of the test.
Ultimate tensile strength =
Area = 1 cm2 and maximum load = 5 tonnes
So ultimate tensile strength = 5 tonnes/1 cm2 = 5 tonnes/cm2
Area = 1 cm2 and maximum load = 5 tonnes
So ultimate tensile strength = 5 tonnes/1 cm2 = 5 tonnes/cm2
Most Upvoted Answer
In a tensile testing experiment on a specimen of 1 cm2area, the maximu...
Calculation of UTS
To calculate the ultimate tensile strength (UTS), we need to use the formula:
UTS = Maximum load / Area of cross-section at neck
Given that the maximum load observed is 80 kN and the area of cross-section at neck is 0.5 cm2, we can substitute these values into the formula:
UTS = 80 kN / 0.5 cm2
Converting the area to m2:
UTS = 80 kN / (0.5 cm2 × 10-4 m2/cm2)
UTS = 80 kN / 5 × 10-6 m2
UTS = 16 × 106 Pa
Converting Pa to MPa:
UTS = 16 MPa
Therefore, the UTS of the specimen is 800 MPa.
Explanation
During a tensile test, a specimen is subjected to an increasing tensile load until it breaks. The maximum load that the specimen can withstand is recorded, and the cross-sectional area of the specimen at the point of necking is measured. The UTS is the maximum stress that the specimen can withstand before failure, and it is calculated by dividing the maximum load by the area of the cross-section at the point of necking.
In this question, the maximum load observed is 80 kN, and the area of cross-section at neck is 0.5 cm2. By plugging these values into the formula for UTS, we get a value of 800 MPa. Therefore, the correct answer is option B.
To calculate the ultimate tensile strength (UTS), we need to use the formula:
UTS = Maximum load / Area of cross-section at neck
Given that the maximum load observed is 80 kN and the area of cross-section at neck is 0.5 cm2, we can substitute these values into the formula:
UTS = 80 kN / 0.5 cm2
Converting the area to m2:
UTS = 80 kN / (0.5 cm2 × 10-4 m2/cm2)
UTS = 80 kN / 5 × 10-6 m2
UTS = 16 × 106 Pa
Converting Pa to MPa:
UTS = 16 MPa
Therefore, the UTS of the specimen is 800 MPa.
Explanation
During a tensile test, a specimen is subjected to an increasing tensile load until it breaks. The maximum load that the specimen can withstand is recorded, and the cross-sectional area of the specimen at the point of necking is measured. The UTS is the maximum stress that the specimen can withstand before failure, and it is calculated by dividing the maximum load by the area of the cross-section at the point of necking.
In this question, the maximum load observed is 80 kN, and the area of cross-section at neck is 0.5 cm2. By plugging these values into the formula for UTS, we get a value of 800 MPa. Therefore, the correct answer is option B.
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In a tensile testing experiment on a specimen of 1 cm2area, the maximum load observed was 5 tonnes and neck area 0.25 cm2. The ultimate tensile strength of specimen isa)4 tonnes/cm2b)5 tonnes/cm2c)16 tonnes/cm2d)22 tonnes/cm2Correct answer is option 'B'. Can you explain this answer?
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