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An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding):
- a)75 m
- b)160 m
- c)150 m
- d)100 m
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An automobile, travelling at 40 km/h, can be stopped at a distance of ...
u = 40 Km/hr
μ = 100/9 m/s
V2 − u2 = 2a × 40
a = −1.54 m m/s2
Now.
S = 160m
μ = 100/9 m/s
V2 − u2 = 2a × 40
a = −1.54 m m/s2
Now.
S = 160m
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Community Answer
An automobile, travelling at 40 km/h, can be stopped at a distance of ...
Given information:
Speed of the automobile, v1 = 40 km/h = 11.11 m/s
Stopping distance at v1, d1 = 40 m
To find:
Minimum stopping distance, d2 at speed v2 = 80 km/h = 22.22 m/s
Solution:
1. Kinematic equation for motion with uniform acceleration:
v² = u² + 2as
where,
u = initial velocity = v1 or v2
v = final velocity = 0 (since the automobile comes to a stop)
a = acceleration
s = distance travelled
2. Calculation of acceleration, a:
From the given information, the automobile can be stopped at a distance of d1 = 40 m when travelling at speed v1 = 11.11 m/s.
Using the above kinematic equation,
0² = (11.11)² + 2a(40)
a = -3.086 m/s² (negative sign indicates deceleration)
3. Calculation of stopping distance, d2:
Using the same kinematic equation,
0² = (22.22)² + 2(-3.086)s
s = 80 m
Therefore, the minimum stopping distance at a speed of 80 km/h is 80 m or option (b) is correct.
Speed of the automobile, v1 = 40 km/h = 11.11 m/s
Stopping distance at v1, d1 = 40 m
To find:
Minimum stopping distance, d2 at speed v2 = 80 km/h = 22.22 m/s
Solution:
1. Kinematic equation for motion with uniform acceleration:
v² = u² + 2as
where,
u = initial velocity = v1 or v2
v = final velocity = 0 (since the automobile comes to a stop)
a = acceleration
s = distance travelled
2. Calculation of acceleration, a:
From the given information, the automobile can be stopped at a distance of d1 = 40 m when travelling at speed v1 = 11.11 m/s.
Using the above kinematic equation,
0² = (11.11)² + 2a(40)
a = -3.086 m/s² (negative sign indicates deceleration)
3. Calculation of stopping distance, d2:
Using the same kinematic equation,
0² = (22.22)² + 2(-3.086)s
s = 80 m
Therefore, the minimum stopping distance at a speed of 80 km/h is 80 m or option (b) is correct.
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An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer?
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An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer?.
An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer?.
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An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of An automobile, travelling at 40 km/h, can be stopped at a distance of 40m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding): a)75 mb)160 mc)150 md)100 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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