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For the set of negative real numbers
A = {x ε R; x< 0}
​Then, sup A is equal to
  • a)
    -1
  • b)
    1
  • c)
    0
  • d)
    2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
For the set of negative real numbersA = {x ε R; x< 0}​...
The set A = {x | x < 0}="" is="" the="" set="" of="" all="" negative="" real="" numbers.="" it="" includes="" numbers="" such="" as="" -1,="" -2,="" -3,="" and="" so="" on.="" the="" set="" does="" not="" include="" zero="" or="" any="" positive="" real="" numbers.="" 0}="" is="" the="" set="" of="" all="" negative="" real="" numbers.="" it="" includes="" numbers="" such="" as="" -1,="" -2,="" -3,="" and="" so="" on.="" the="" set="" does="" not="" include="" zero="" or="" any="" positive="" real="" />
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For the set of negative real numbersA = {x ε R; x< 0}​...
C you can see, 0 is the no. which is lub of the set A.
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For the set of negative real numbersA = {x ε R; x< 0}​Then, sup A is equal toa)-1b)1c)0d)2Correct answer is option 'C'. Can you explain this answer?
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