The closed interval (0, 1) havea)maximal element onlyb)minimal element...
The closed interval (0, 1) is a subset of the real numbers that contains all the real numbers between 0 and 1, including 0 and 1 themselves. In this interval, there are no maximal or minimal elements. Let's understand why.
Maximal element:
A maximal element in a set is an element that is greater than or equal to every other element in the set. In the closed interval (0, 1), there is no element that is greater than or equal to every other element because for any element x in the interval, there exists another element y such that y > x. For example, if x = 0.5, then y = 0.6 is greater than x. Therefore, the closed interval (0, 1) does not have a maximal element.
Minimal element:
A minimal element in a set is an element that is less than or equal to every other element in the set. In the closed interval (0, 1), there is no element that is less than or equal to every other element because for any element x in the interval, there exists another element y such that y < x.="" for="" example,="" if="" x="0.5," then="" y="0.4" is="" less="" than="" x.="" therefore,="" the="" closed="" interval="" (0,="" 1)="" does="" not="" have="" a="" minimal="" />
Explanation:
The closed interval (0, 1) is a bounded interval that includes both its endpoints, 0 and 1. However, it does not have a maximal or minimal element. This is because there is always another element in the interval that is greater than any given element (no maximal element) or less than any given element (no minimal element).
The absence of maximal and minimal elements in the closed interval (0, 1) is a result of its nature as a continuous set. Continuous sets do not have discrete elements that can be identified as the largest or smallest in the set. Instead, there is always another element that is closer to either end of the interval.
In conclusion, the closed interval (0, 1) does not have maximal or minimal elements.
The closed interval (0, 1) havea)maximal element onlyb)minimal element...
Maximul and minimal element are 1 & 0 ,since it is open interval ,1 & 0 are not in the set Hence,D is correct