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The maximum value of the solution y (t) of the differential equation with initial conditions = 0 and y(0) = 1 for 0 is
  • a)
    1
  • b)
    2
  • c)
    p
  • d)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The maximum value of the solution y (t) of the differential equation ...

y = A cos x + B sin x
y(0) = 1
Therefore 1 = A × 1 + B × 0
 A = 1
y = – A sin x + B cos x
= 1
1 = – A × 0 + B × 1
 B = 1
so, y = cos x + sin x

=
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The maximum value of the solution y (t) of the differential equation with initial conditions = 0 and y(0) = 1 for 0 is a)1b)2c)pd) Correct answer is option 'D'. Can you explain this answer?
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