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Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:
- a)XeOF4 (+ 6) and XeO2F2 (+6)
- b)XeOF4 (+ 6) and XeO3 (+6)
- c)XeO2F2 (+ 6) and XeO2 (+4)
- d)XeO2(+ 4) and XeO3 (+6)
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Xenon hexafluoride on partial hydrolysis produces compounds 'X'...
Xe F6 + H2O → XeO F4 + 2HF
XeF6 + 2H2O → XeO2F2 + 4HF
XeF6 + 2H2O → XeO2F2 + 4HF
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Xenon hexafluoride on partial hydrolysis produces compounds 'X'...
Xenon Hexafluoride and Hydrolysis
Xenon hexafluoride (XeF6) undergoes partial hydrolysis when it reacts with water, leading to the formation of products X and Y.
Products Formation
- The hydrolysis of XeF6 typically produces:
- Compound X: Xenon Oxyfluoride (XeOF4)
- Compound Y: Xenon Oxyfluoride (XeO2F2)
Oxidation States of Xenon
- In both compounds, the oxidation state of xenon is +6:
- XeOF4: The presence of one oxygen atom and four fluorine atoms leads to an oxidation state of +6.
- XeO2F2: Similar reasoning applies, where the xenon retains a +6 oxidation state due to the bonding with two oxygen and two fluorine atoms.
Option Analysis
- The correct answer is option 'A' because:
- XeOF4 has an oxidation state of +6.
- XeO2F2 also has an oxidation state of +6.
- Other options can be eliminated based on incorrect oxidation states or incorrect product formation.
Significance of Oxidation States
- Understanding the oxidation states is crucial in predicting the reactivity and stability of xenon compounds.
- The +6 state indicates a strong oxidizing capability, which is a key feature of xenon compounds.
In summary, the hydrolysis of xenon hexafluoride produces XeOF4 and XeO2F2, both maintaining xenon in the +6 oxidation state, making option 'A' the correct choice.
Xenon hexafluoride (XeF6) undergoes partial hydrolysis when it reacts with water, leading to the formation of products X and Y.
Products Formation
- The hydrolysis of XeF6 typically produces:
- Compound X: Xenon Oxyfluoride (XeOF4)
- Compound Y: Xenon Oxyfluoride (XeO2F2)
Oxidation States of Xenon
- In both compounds, the oxidation state of xenon is +6:
- XeOF4: The presence of one oxygen atom and four fluorine atoms leads to an oxidation state of +6.
- XeO2F2: Similar reasoning applies, where the xenon retains a +6 oxidation state due to the bonding with two oxygen and two fluorine atoms.
Option Analysis
- The correct answer is option 'A' because:
- XeOF4 has an oxidation state of +6.
- XeO2F2 also has an oxidation state of +6.
- Other options can be eliminated based on incorrect oxidation states or incorrect product formation.
Significance of Oxidation States
- Understanding the oxidation states is crucial in predicting the reactivity and stability of xenon compounds.
- The +6 state indicates a strong oxidizing capability, which is a key feature of xenon compounds.
In summary, the hydrolysis of xenon hexafluoride produces XeOF4 and XeO2F2, both maintaining xenon in the +6 oxidation state, making option 'A' the correct choice.
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Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer?.
Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer?.
Solutions for Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively:a)XeOF4 (+ 6) and XeO2F2 (+6)b)XeOF4 (+ 6) and XeO3 (+6)c)XeO2F2 (+ 6) and XeO2 (+4)d)XeO2(+ 4) and XeO3 (+6)Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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