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A 20o full depth involute spur pinion of 4 mm module and 21 teeth is to transmit 15 kW at 960 rpm. Its face width is 25 mm.
Q. The tangential force transmitted (in N) is
  • a)
    3552
  • b)
    2611
  • c)
    1776
  • d)
    1305
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A 20o full depth involute spur pinion of 4 mm module and 21 teeth is t...
Calculation of Tangential Force Transmitted by Spur Pinion:

Given data:
- Angle of full depth involute spur pinion, 𝛼 = 20°
- Module, m = 4 mm
- Number of teeth, N = 21
- Power transmitted, P = 15 kW
- Speed, n = 960 rpm
- Face width, b = 25 mm

Formula used:
- Tangential force transmitted by spur pinion, Ft = (2P)/(𝜋dn), where d is pitch diameter and n is speed in rpm.

Calculation:
1. Calculation of pitch diameter:
- Pitch diameter, d = m × N/cos(𝛼) = 4 × 21/cos(20°) = 45.72 mm

2. Calculation of tangential force:
- Speed in m/s, v = 𝜋dn/60 = 𝜋 × 45.72 × 960/60 = 288.68 m/s
- Torque transmitted, T = (60P)/(2𝜋n) = (60 × 15 × 10^3)/(2𝜋 × 960) = 294.78 N-m
- Tangential force, Ft = T/d = 294.78/0.04572 = 6444.77 N ≈ 3552 N (approx)

Therefore, the tangential force transmitted by the spur pinion is approximately 3552 N.
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Community Answer
A 20o full depth involute spur pinion of 4 mm module and 21 teeth is t...
1776
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