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A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material constant K = 5/3 is inserted between the plates, the magnitude of the induced charge will be : 
  • a)
    1.2 n C
  • b)
    0.3 n C
  • c)
    2.4 n C
  • d)
    0.9 n C 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A parallel plate capacitor of capacitance 90 pF is connected to a batt...
qi = C0V
= 90 x 10-12 x 20
= 1800 x 10-12
= 1.8nC
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Community Answer
A parallel plate capacitor of capacitance 90 pF is connected to a batt...
Option a will be correct ans
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A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material constant K = 5/3is inserted between the plates, the magnitude of theinduced charge will be :a)1.2 n Cb)0.3 n Cc)2.4 n Cd)0.9 n CCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material constant K = 5/3is inserted between the plates, the magnitude of theinduced charge will be :a)1.2 n Cb)0.3 n Cc)2.4 n Cd)0.9 n CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material constant K = 5/3is inserted between the plates, the magnitude of theinduced charge will be :a)1.2 n Cb)0.3 n Cc)2.4 n Cd)0.9 n CCorrect answer is option 'A'. Can you explain this answer?.
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