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Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.
  • a)
    (a) 189 K (b) 2.7 kJ
  • b)
    (a) 195 K (b) -2.7 kJ
  • c)
    (a) 189 K (b) -2.7 kJ
  • d)
    (a) 195 K (b) 2.7 kJ
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two moles of an ideal monoatomic gas occupies a volume V at 270C. The ...
Initially n = 2, v, T= 300k
Finally Vd = 2v
Gas is monoatomic, So, r = 5/3
So, 


Since gas undergoes expensed.

 
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Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.a)(a) 189 K (b) 2.7 kJb)(a) 195 K (b) -2.7 kJc)(a) 189 K (b) -2.7 kJd)(a) 195 K (b) 2.7 kJCorrect answer is option 'C'. Can you explain this answer?
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Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.a)(a) 189 K (b) 2.7 kJb)(a) 195 K (b) -2.7 kJc)(a) 189 K (b) -2.7 kJd)(a) 195 K (b) 2.7 kJCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.a)(a) 189 K (b) 2.7 kJb)(a) 195 K (b) -2.7 kJc)(a) 189 K (b) -2.7 kJd)(a) 195 K (b) 2.7 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.a)(a) 189 K (b) 2.7 kJb)(a) 195 K (b) -2.7 kJc)(a) 189 K (b) -2.7 kJd)(a) 195 K (b) 2.7 kJCorrect answer is option 'C'. Can you explain this answer?.
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