Mechanical Engineering Exam > Mechanical Engineering Questions > The variation of saturation pressure with sat...
Start Learning for Free
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latent heat of vaporization using Clausius clapeyron equation?
- a)16000 kJ/kg
- b)1600 kJ/kg
- c)1000 kJ/kg
- d)160 kK/kg
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The variation of saturation pressure with saturation temperature for a...
Most Upvoted Answer
The variation of saturation pressure with saturation temperature for a...
Given data:
Saturation temperature (T) = 400 K
Variation of saturation pressure with saturation temperature (dp/dT) = 0.1 bar/K
Specific volume of saturated liquid (vf) = 0.251 m³/kg
Specific volume of dry saturated vapor (vg) = 0.001 m³/kg
Formula:
The Clausius-Clapeyron equation is given by:
ln(P2/P1) = (ΔHvap/R)(1/T1 - 1/T2)
Where,
P1 and P2 are the initial and final saturation pressures,
T1 and T2 are the initial and final saturation temperatures,
ΔHvap is the latent heat of vaporization, and
R is the specific gas constant.
Calculation:
We are given the variation of saturation pressure with saturation temperature (dp/dT) = 0.1 bar/K. This means that for every 1 K increase in temperature, the pressure increases by 0.1 bar.
To find the latent heat of vaporization (ΔHvap), we need to find the difference in saturation pressures (ΔP) and saturation temperatures (ΔT) between the liquid and vapor states.
ΔP = P2 - P1
ΔT = T2 - T1
Using the given data, we can calculate the values of P1, P2, T1, and T2:
P1 = saturation pressure at T1 = P2 - dp/dT * ΔT
P2 = saturation pressure at T2 = P1 + dp/dT * ΔT
T1 = 400 K
T2 = 400 K
Substituting these values into the Clausius-Clapeyron equation, we have:
ln((P2 - dp/dT * ΔT)/P1) = (ΔHvap/R)(1/T1 - 1/T2)
Simplifying the equation, we get:
ΔHvap/R = (1/T1 - 1/T2) * ln((P2 - dp/dT * ΔT)/P1)
Since R is the specific gas constant, we can assume its value to be constant.
Now, we can substitute the known values into the equation and calculate ΔHvap:
ΔHvap = R * (1/T1 - 1/T2) * ln((P2 - dp/dT * ΔT)/P1)
Using the given specific gas constant and the calculated values of ΔT, P1, and P2, we can solve for ΔHvap:
ΔHvap = (8.314 J/mol K) * (1/400 K - 1/400 K) * ln((P2 - 0.1 bar/K * 0 K)/P1)
Converting the result from J/mol to kJ/kg, we find that the value of ΔHvap is approximately 1000 kJ/kg.
Therefore, the correct answer is option C) 1000 kJ/kg.
Saturation temperature (T) = 400 K
Variation of saturation pressure with saturation temperature (dp/dT) = 0.1 bar/K
Specific volume of saturated liquid (vf) = 0.251 m³/kg
Specific volume of dry saturated vapor (vg) = 0.001 m³/kg
Formula:
The Clausius-Clapeyron equation is given by:
ln(P2/P1) = (ΔHvap/R)(1/T1 - 1/T2)
Where,
P1 and P2 are the initial and final saturation pressures,
T1 and T2 are the initial and final saturation temperatures,
ΔHvap is the latent heat of vaporization, and
R is the specific gas constant.
Calculation:
We are given the variation of saturation pressure with saturation temperature (dp/dT) = 0.1 bar/K. This means that for every 1 K increase in temperature, the pressure increases by 0.1 bar.
To find the latent heat of vaporization (ΔHvap), we need to find the difference in saturation pressures (ΔP) and saturation temperatures (ΔT) between the liquid and vapor states.
ΔP = P2 - P1
ΔT = T2 - T1
Using the given data, we can calculate the values of P1, P2, T1, and T2:
P1 = saturation pressure at T1 = P2 - dp/dT * ΔT
P2 = saturation pressure at T2 = P1 + dp/dT * ΔT
T1 = 400 K
T2 = 400 K
Substituting these values into the Clausius-Clapeyron equation, we have:
ln((P2 - dp/dT * ΔT)/P1) = (ΔHvap/R)(1/T1 - 1/T2)
Simplifying the equation, we get:
ΔHvap/R = (1/T1 - 1/T2) * ln((P2 - dp/dT * ΔT)/P1)
Since R is the specific gas constant, we can assume its value to be constant.
Now, we can substitute the known values into the equation and calculate ΔHvap:
ΔHvap = R * (1/T1 - 1/T2) * ln((P2 - dp/dT * ΔT)/P1)
Using the given specific gas constant and the calculated values of ΔT, P1, and P2, we can solve for ΔHvap:
ΔHvap = (8.314 J/mol K) * (1/400 K - 1/400 K) * ln((P2 - 0.1 bar/K * 0 K)/P1)
Converting the result from J/mol to kJ/kg, we find that the value of ΔHvap is approximately 1000 kJ/kg.
Therefore, the correct answer is option C) 1000 kJ/kg.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Top Courses for Mechanical EngineeringView all
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer?
Question Description
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer?.
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg. What will be value of latentheat of vaporization using Clausius clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kK/kgCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup