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The angular width of the central maximum in a single slit diffraction pattern is 600. The width of the slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at a distance of 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance ?
(i.e. distance between the centres of each slit.)
  • a)
    25μm
  • b)
    50μm
  • c)
    75μm
  • d)
    100μm
Correct answer is option 'A'. Can you explain this answer?
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The angular width of the central maximum in a single slit diffraction ...

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The angular width of the central maximum in a single slit diffraction ...
To find the angular width of the central maximum in a single slit diffraction pattern, we can use the formula:

θ = λ / w

where θ is the angular width, λ is the wavelength of light, and w is the width of the slit.

In this case, the angular width is given as 600. We can rearrange the formula to solve for the wavelength:

λ = θ * w

Substituting the given values, we have:

λ = 600 * 1

λ = 600 nm

Therefore, the wavelength of light is 600 nm.
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The angular width of the central maximum in a single slit diffraction pattern is 600. The width of the slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at adistance of 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance ?(i.e. distance between the centres of each slit.)a)25μmb)50μmc)75μmd)100μmCorrect answer is option 'A'. Can you explain this answer?
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The angular width of the central maximum in a single slit diffraction pattern is 600. The width of the slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at adistance of 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance ?(i.e. distance between the centres of each slit.)a)25μmb)50μmc)75μmd)100μmCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The angular width of the central maximum in a single slit diffraction pattern is 600. The width of the slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at adistance of 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance ?(i.e. distance between the centres of each slit.)a)25μmb)50μmc)75μmd)100μmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The angular width of the central maximum in a single slit diffraction pattern is 600. The width of the slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at adistance of 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance ?(i.e. distance between the centres of each slit.)a)25μmb)50μmc)75μmd)100μmCorrect answer is option 'A'. Can you explain this answer?.
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