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A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:
- a)3 mm
- b)9 mm
- c)4.5 mm
- d)1.5 mm
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A single slit of width 0.1 mm is illuminated by a parallel beam of lig...
a = 0.1 mm = 10–4
λ = 6000 × 10-10
= 6 × 10-7
D = 0.5 m
for 3rd dark
a sin θ = 3λ
λ = 6000 × 10-10
= 6 × 10-7
D = 0.5 m
for 3rd dark
a sin θ = 3λ
Most Upvoted Answer
A single slit of width 0.1 mm is illuminated by a parallel beam of lig...
To find the angle at which the first minimum of the single-slit diffraction pattern occurs, we can use the formula:
sin(θ) = λ / (a * n)
where θ is the angle, λ is the wavelength of light, a is the width of the slit, and n is the order of the minimum.
In this case, the width of the slit is 0.1 mm, which is equal to 0.1 * 10^-3 m.
The wavelength of light is 6000 Å, which is equal to 6000 * 10^-10 m.
We want to find the angle at which the first minimum occurs, so n = 1.
Plugging these values into the formula, we get:
sin(θ) = (6000 * 10^-10) / (0.1 * 10^-3 * 1)
Simplifying, we get:
sin(θ) = 0.06
To find the angle, we can take the inverse sine of both sides:
θ = sin^(-1)(0.06)
Using a calculator, we find:
θ ≈ 3.49 degrees
Therefore, the angle at which the first minimum of the single-slit diffraction pattern occurs is approximately 3.49 degrees.
sin(θ) = λ / (a * n)
where θ is the angle, λ is the wavelength of light, a is the width of the slit, and n is the order of the minimum.
In this case, the width of the slit is 0.1 mm, which is equal to 0.1 * 10^-3 m.
The wavelength of light is 6000 Å, which is equal to 6000 * 10^-10 m.
We want to find the angle at which the first minimum occurs, so n = 1.
Plugging these values into the formula, we get:
sin(θ) = (6000 * 10^-10) / (0.1 * 10^-3 * 1)
Simplifying, we get:
sin(θ) = 0.06
To find the angle, we can take the inverse sine of both sides:
θ = sin^(-1)(0.06)
Using a calculator, we find:
θ ≈ 3.49 degrees
Therefore, the angle at which the first minimum of the single-slit diffraction pattern occurs is approximately 3.49 degrees.
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A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer?
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A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer?.
A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is:a)3 mmb)9 mmc)4.5 mmd)1.5 mmCorrect answer is option 'B'. Can you explain this answer?.
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