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If f(x) is real-valued function defined on [0, ∞] such that f(0) = 0 and then the function h(x)  is
  • a)
    increasing in [0,∞]
  • b)
    decreasing in [0, 1]
  • c)
    increasing in [0, 1] and decreasing in [1, ∞]
  • d)
    decreasing in [0, 1] and increasing in [ 1 , ∞]
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If f(x) is real-valued function defined on [0, ∞] such that f(0)...
Given that,


Since, f''(x) > 0 and x > 0, therefore g'(x) > 0, 0 => g (x) is strictly increasing function in [0, ∞]
since, h'(x)
=> h'(x) > 0,
or h (x) is increasing in [0, ∞]
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If f(x) is real-valued function defined on [0, ∞] such that f(0)...
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Community Answer
If f(x) is real-valued function defined on [0, ∞] such that f(0)...
Given that,


Since, f''(x) > 0 and x > 0, therefore g'(x) > 0, 0 => g (x) is strictly increasing function in [0, ∞]
since, h'(x)
=> h'(x) > 0,
or h (x) is increasing in [0, ∞]
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If f(x) is real-valued function defined on [0, ∞] such that f(0) = 0 and then the function h(x)isa)increasing in [0,∞]b)decreasing in [0, 1]c)increasing in [0, 1] and decreasing in [1, ∞]d)decreasing in [0, 1] and increasing in [ 1 , ∞]Correct answer is option 'A'. Can you explain this answer?
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