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A reversible power cycle operates with temperature lim its of 800 K and 300 K. If it takes 560kj of heat, then what would be the unavailable work?
  • a)
    180 kJ
  • b)
    190 kJ
  • c)
    200 kJ
  • d)
    210 kJ
Correct answer is option 'D'. Can you explain this answer?
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Given:
Temperature limits: T1 = 800 K, T2 = 300 K
Heat supplied: Q = 560 kJ

To find: Unavailable work

The efficiency of a reversible power cycle is given by the formula:

η = 1 - (T2 / T1)

To find the unavailable work, we can use the formula:

Unavailable work = Q - W

where W is the work output.

Since the cycle is reversible, the work output is equal to the work input, so W = Q.

Therefore, the unavailable work can be calculated as:

Unavailable work = Q - W = Q - Q = 0

Explanation:

The unavailable work represents the energy that cannot be converted into useful work in a reversible power cycle. In this case, since the temperature limits of the cycle are given, we can calculate the efficiency of the cycle using the formula mentioned above.

η = 1 - (T2 / T1)
= 1 - (300 / 800)
= 1 - 0.375
= 0.625

The efficiency of the cycle is 0.625, which means that 62.5% of the heat input can be converted into useful work. The remaining 37.5% is the unavailable work.

Since the heat supplied is given as 560 kJ, the unavailable work can be calculated as:

Unavailable work = 0.375 * Q
= 0.375 * 560 kJ
= 210 kJ

Therefore, the unavailable work is 210 kJ, which corresponds to option D.
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