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A bomb initially at rest explodes by it self into three equal mass fragments. The velocities of two fragments are ( 3  + 2 ) m/s and (_ _ 4) m/s. The velocity of the third fragment is (in m/s)-
  • a)
    2 + 2
  • b)
    2 _ 2
  • c)
    _ 2 + 2
  • d)
    _2 _ 2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A bomb initially at rest explodes by it self into three equal mass fra...
Applying law of conservation of momentum,
Mv= m1v1 + m2v2 +m3v3
As initially M is at rest ,v= O
Also m1=m2 =m3 = m (equal masses)
We have m(v1 +v2+ v3) = O
v1+ v2 = -v3
(3i+2j)+(-i-4j) = -v3
3i+2j-i-4j =2i-2j =-v3
v3 = -2i+2j
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Most Upvoted Answer
A bomb initially at rest explodes by it self into three equal mass fra...
You can apply law of conservation of momentum,

Mv= m1v1 + m2v2 +m3v3

as initially M is at rest ,v= O

also m1=m2 =m3 = m (equal masses)


We have m(v1 +v2+ v3) = O


v1+ v2 = -v3

(3i+2j)+(-i-4j) = -v3

3i+2j-i-4j =2i-2j =-v3


v3 = -2i+2j

option c
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Community Answer
A bomb initially at rest explodes by it self into three equal mass fra...
Applying law of conservation of momentum,
Mv= m1v1 + m2v2 +m3v3
As initially M is at rest ,v= O
Also m1=m2 =m3 = m (equal masses)
We have m(v1 +v2+ v3) = O
v1+ v2 = -v3
(3i+2j)+(-i-4j) = -v3
3i+2j-i-4j =2i-2j =-v3
v3 = -2i+2j
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A bomb initially at rest explodes by it self into three equal mass fragments. The velocities of two fragments are ( 3+ 2) m/s and (__ 4) m/s. The velocity of the third fragment is (in m/s)-a)2+ 2b)2_ 2c)_ 2+ 2d)_2_ 2Correct answer is option 'C'. Can you explain this answer?
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