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3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is
  • a)
    Six
  • b)
    Zero
  • c)
    Two
  • d)
    Four
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms...
D option as there are 2 chiral centres present in the final product and according to the formula , no. of stereoisomers =2^n ( n= no. of stereocentre).. so 2^2=4
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3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product isa)Sixb)Zeroc)Twod)FourCorrect answer is option 'D'. Can you explain this answer?
Question Description
3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product isa)Sixb)Zeroc)Twod)FourCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product isa)Sixb)Zeroc)Twod)FourCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product isa)Sixb)Zeroc)Twod)FourCorrect answer is option 'D'. Can you explain this answer?.
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