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3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:
(Answer up to the nearest integer)
(Answer up to the nearest integer)
Correct answer is '4'. Can you explain this answer?
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3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms...
The product 2-bromo-3-methyl pentane is asymmetrical with 2 chiral carbons.
Number of optical isomers = 2n = 22 = 4
Number of optical isomers = 2n = 22 = 4
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3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms...
Understanding the Reaction of 3-Methylpent-2-ene with HBr
When 3-methylpent-2-ene reacts with HBr in the presence of peroxides, the reaction proceeds via a free radical mechanism, which leads to anti-Markovnikov addition. This means that the bromine atom adds to the less substituted carbon of the double bond.
Structure of the Product
- The double bond in 3-methylpent-2-ene is between the second and third carbon.
- In the presence of HBr and peroxide, bromine adds to the first carbon and hydrogen to the second carbon, leading to the formation of 1-bromo-3-methylpentane.
Stereochemistry and Isomers
- The carbon atom at position 2 (where hydrogen adds) becomes chiral after the reaction due to the presence of four different substituents.
- This chirality introduces the possibility of stereoisomerism.
Counting Stereoisomers
- For a chiral center, there are 2 possible configurations (R and S).
- Additionally, the product features another carbon (the one at position 3) that also has two different substituents (the bromine atom and the rest of the carbon chain), which results in further stereoisomerism.
Conclusion
- Therefore, for the compound formed, we can have:
- 2 configurations from the chiral center at carbon 2.
- 2 configurations from the stereocenter at carbon 3.
- Multiplying these gives us \(2 \times 2 = 4\) possible stereoisomers for the product.
So, the number of possible stereoisomers for the addition product is indeed **4**.
When 3-methylpent-2-ene reacts with HBr in the presence of peroxides, the reaction proceeds via a free radical mechanism, which leads to anti-Markovnikov addition. This means that the bromine atom adds to the less substituted carbon of the double bond.
Structure of the Product
- The double bond in 3-methylpent-2-ene is between the second and third carbon.
- In the presence of HBr and peroxide, bromine adds to the first carbon and hydrogen to the second carbon, leading to the formation of 1-bromo-3-methylpentane.
Stereochemistry and Isomers
- The carbon atom at position 2 (where hydrogen adds) becomes chiral after the reaction due to the presence of four different substituents.
- This chirality introduces the possibility of stereoisomerism.
Counting Stereoisomers
- For a chiral center, there are 2 possible configurations (R and S).
- Additionally, the product features another carbon (the one at position 3) that also has two different substituents (the bromine atom and the rest of the carbon chain), which results in further stereoisomerism.
Conclusion
- Therefore, for the compound formed, we can have:
- 2 configurations from the chiral center at carbon 2.
- 2 configurations from the stereocenter at carbon 3.
- Multiplying these gives us \(2 \times 2 = 4\) possible stereoisomers for the product.
So, the number of possible stereoisomers for the addition product is indeed **4**.
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3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer?
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3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer?.
3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3-Methyl pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:(Answer up to the nearest integer)Correct answer is '4'. Can you explain this answer?.
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